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siddharth
 3 years ago
Best ResponseYou've already chosen the best response.1Derivative of an expression of the form of \[ax^n\] is \[nax^{n1}\]

msayer3
 3 years ago
Best ResponseYou've already chosen the best response.1\[(4\times3)x^{31} + (5\times1)x ^{11}\]

msayer3
 3 years ago
Best ResponseYou've already chosen the best response.1the basic rule of derivative applies  where you take the exponent and multiply that to coefficient. Exponent you originally have will be subtracted by 1 which results in x^2 and x^0 term above.

superduper
 3 years ago
Best ResponseYou've already chosen the best response.0thanks guys this is really helping

siddharth
 3 years ago
Best ResponseYou've already chosen the best response.1also, d(x+y) = d(x) + d(y)

msayer3
 3 years ago
Best ResponseYou've already chosen the best response.1be sure to practice  that way you understand the application of the rule
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