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anonymous
 5 years ago
I am unable to solve the two simultaneous equations: 0.991=0.0266x+0.0835y, 0.325=0.0499x+0.0077y. Could you help?
anonymous
 5 years ago
I am unable to solve the two simultaneous equations: 0.991=0.0266x+0.0835y, 0.325=0.0499x+0.0077y. Could you help?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Use the fisrt equation to find y=f(x) on replace the y's expression found in the second equation to compute x and you'll find y (I have x=0.523...)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if i were doing it i would clear the decimals and write \[266x+835y=9110\] \[499x+77y=3250\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0then i would go slap the math teacher for giving me such annoying numbers to work with. then i would use some computer algebra system to solve

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0well not that hard when you ask the machine. i got \[x=\frac{ 1950680}{396183} \]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how much arithmetic do you wan to do for a problem like this?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The thought police will be after u for suggesting an assault on apoor math teacher...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok a mild slap with a kleenex. but really, who would even want to know such a thing. if this problem arose naturally from some actual data, then fine. get out the software and find your answer.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Either u or olive is a bit out...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i used a machine. i have no stake in this game

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I guess olive used her machine wrong, I'm not going to check it though.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0She got the principle right, that's the main thing...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Thanks for your help. By the way, this is chemistry...determining unknown concentrations.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0That's a reasonable excuse, no need to slap the chem teacher, then:)
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