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LeoMessi
Quick question to clarify my understanding of how to find the gradient of a function: In practice exam 2b, Problem #1: (x^2)(y^2)-x
all right, to find the gradient of this function, \[f(x,y) = x^2y^2-x\]
you find the partial derivative of f with regard to x, and then with regard to y
\[<\partial f/\partial x, \partial f/\partial y>\]
all right, so first, partial w/re to x is 2x*y^2-1
and partial w/re to y is 2x^2*y
looks good, so format would be: \[<2xy^2-1, 2x^2y>\]
right, excellent, just wanted to make sure my brain was working properly ;)
now you can just plug in the point to consider like in the prac. exam problem