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LeoMessi
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Quick question to clarify my understanding of how to find the gradient of a function: In practice exam 2b, Problem #1: (x^2)(y^2)x
 3 years ago
 3 years ago
LeoMessi Group Title
Quick question to clarify my understanding of how to find the gradient of a function: In practice exam 2b, Problem #1: (x^2)(y^2)x
 3 years ago
 3 years ago

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Ackbar Group TitleBest ResponseYou've already chosen the best response.2
all right, to find the gradient of this function, \[f(x,y) = x^2y^2x\]
 3 years ago

Ackbar Group TitleBest ResponseYou've already chosen the best response.2
you find the partial derivative of f with regard to x, and then with regard to y
 3 years ago

Ackbar Group TitleBest ResponseYou've already chosen the best response.2
\[<\partial f/\partial x, \partial f/\partial y>\]
 3 years ago

LeoMessi Group TitleBest ResponseYou've already chosen the best response.0
all right, so first, partial w/re to x is 2x*y^21
 3 years ago

LeoMessi Group TitleBest ResponseYou've already chosen the best response.0
and partial w/re to y is 2x^2*y
 3 years ago

Ackbar Group TitleBest ResponseYou've already chosen the best response.2
looks good, so format would be: \[<2xy^21, 2x^2y>\]
 3 years ago

LeoMessi Group TitleBest ResponseYou've already chosen the best response.0
right, excellent, just wanted to make sure my brain was working properly ;)
 3 years ago

Ackbar Group TitleBest ResponseYou've already chosen the best response.2
now you can just plug in the point to consider like in the prac. exam problem
 3 years ago
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