## LeoMessi 3 years ago Quick question to clarify my understanding of how to find the gradient of a function: In practice exam 2b, Problem #1: (x^2)(y^2)-x

1. Ackbar

all right, to find the gradient of this function, $f(x,y) = x^2y^2-x$

2. Ackbar

you find the partial derivative of f with regard to x, and then with regard to y

3. Ackbar

$<\partial f/\partial x, \partial f/\partial y>$

4. LeoMessi

all right, so first, partial w/re to x is 2x*y^2-1

5. LeoMessi

and partial w/re to y is 2x^2*y

6. Ackbar

looks good, so format would be: $<2xy^2-1, 2x^2y>$

7. LeoMessi

right, excellent, just wanted to make sure my brain was working properly ;)

8. Ackbar

now you can just plug in the point to consider like in the prac. exam problem

9. sunnyd48

idk.

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