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How to evaluate -> (5^-4 - 5^-6)/(5^-3 +5^-5)

Mathematics
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bet you got the idea now. write it without the negative exponents. then clear the fractions
Okay so:
\[\frac{5^{-4} - 5^{-6}}{5^{-3} +5^{-5}}\] muttiply top and bottom by \[5^6\]

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Other answers:

I got (1/5^4 - 1/5^6)/ (1/5^3 +1/5^5)
wait. How come I have to multiply top and bottom by 5^6?
that will clear the fractions. \[5^{-4}\times 5^6=5^2\]
if you want you can write this in fraction notation. then you will see that you should multiply top and bottom by \[5^6\]
i will write it out if you like
please do, thanks
\[\frac{5^{-4}-5^{-6}}{5^{-3}+5^{-5}}\times \frac{5^6}{5^6}\]
\[\frac{5^2-1}{5^3+5}\] is the second line clear?
pardon?
i added the exponents, and i chose \[5^6\] so that they would all be positive
okay
because i want to evaluate the numbers, i need the exponents to be positive
mmhm
now i can see what the numbers are. numerator is 25+1=26
denominator is 125+5=130
Isn't the numerator 25-1?
oops yes
Okay, that's great, thanks :) I was making it way more complicated thn it needed to be
i would like to say that was a "typo" but i guess it was a mistake. in any case you have the answer, it is \[\frac{24}{130}=\frac{12}{65}\]
good! yw
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