A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 5 years ago
lim┬(x→π/2)〖(π(π2x) tan〖(xπ/2)〗)/(2(xπ) 〖cos〗^2 x)〗
anonymous
 5 years ago
lim┬(x→π/2)〖(π(π2x) tan〖(xπ/2)〗)/(2(xπ) 〖cos〗^2 x)〗

This Question is Closed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0this is limit of trygonometry, i put it on the ms.word

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Thats indeterminate (0/0) so you would do l'hospital's rule. Have you done that?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes, i have done. but, i'm stuck in trygonometry. can you do that?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The functions involved in the limit are arbitrary as long as they are easily differentiable and the limits actually exist. So taking the derivatives you have: \[\frac{\pi}{2}\lim_{x \rightarrow \frac{\pi}{2}}\frac{(2)(\tan(x\frac{\pi}{2}))+(\pi2x)\sec(x\frac{\pi}{2})\tan(x\frac{\pi}{2})}{\cos^2(x)+(x\pi)(2)(\sin(x))\cos(x))}\] However you notice this is still undeterminate. (0/0) so you have to differentiate it again.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So differentiate it again: \[\frac{\pi}{2}\lim_{x \rightarrow \frac{\pi}{2}}\frac{2 \pi \csc^3(x) (2 \sin(x)+(\pi2 x) \cos(x))}{4 (\pix) \cos(2 x)4 \sin(2 x)}\] Evaluating this should give you 2.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0No problem, sorry its so gross looking :/

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it's okay, you help me anyway :)
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.