Maddiie
  • Maddiie
In a paragraph, describe how to simplify each expression. 16 1/2 Square root 100
Mathematics
  • Stacey Warren - Expert brainly.com
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chestercat
  • chestercat
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anonymous
  • anonymous
????????? why don't u use the equation box to write yr question...
Maddiie
  • Maddiie
In a paragraph, describe how to simplify each expression. 16 1/2 \[\sqrt{100}\]
anonymous
  • anonymous
is the first one \[16^{1/2}\] ???

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Maddiie
  • Maddiie
yes
anonymous
  • anonymous
pls note that \[x ^{1/2} = \sqrt{x}\]
Maddiie
  • Maddiie
why is that
anonymous
  • anonymous
okay I will explain thru an example...
Maddiie
  • Maddiie
ok awesome
anonymous
  • anonymous
u know that \[\sqrt{4}= 2\] also \[(4)^{1/2} = (2^{2})^{1/2} = 2^{2*1/2} = 2^{1}=2\]
anonymous
  • anonymous
so we find that \[\sqrt{4} = (4)^{1/2}\] because both give same result i.e. 2
Maddiie
  • Maddiie
\[({8}^2)\]
Maddiie
  • Maddiie
confused
anonymous
  • anonymous
so we can solve the first one as \[(16)^{1/2} = (4^{2})^{1/2} = 4^{2*1/2} = 4^{1}=4\]
anonymous
  • anonymous
what is confusing u???
Maddiie
  • Maddiie
Oh because 4x4=16 right
anonymous
  • anonymous
yes
Maddiie
  • Maddiie
So \[\sqrt{100}= 10 \]
anonymous
  • anonymous
You might want to introduce and include rules of exponents and roots as part of your explanation.
anonymous
  • anonymous
yes that is correct
Maddiie
  • Maddiie
ok i understood the steps now
Maddiie
  • Maddiie
ok i understood the steps now
anonymous
  • anonymous
see square and root are opposite operations. so when they occur together, they cancel each other out.... we can show the working for root100 as follows : \[\sqrt{100}=\sqrt{10^{2}}=10\] the square inside and root outside cancel each other out
anonymous
  • anonymous
are u familiar with exponential laws???
Maddiie
  • Maddiie
makes sense
Maddiie
  • Maddiie
not really but i can try to find it in my book
anonymous
  • anonymous
yes, u shud have all the laws in front of you and slowly try to learn them by heart....
Maddiie
  • Maddiie
ok thank u
anonymous
  • anonymous
u r welcome, just keep in mind... \[\sqrt{x}=x ^{1/2}\] \[\sqrt[3]{x}=x ^{1/3}\] \[\sqrt[4]{x}=x ^{1/4}\] and so on....

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