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 3 years ago
In a paragraph, describe how to simplify each expression.
16 1/2
Square root 100
 3 years ago
In a paragraph, describe how to simplify each expression. 16 1/2 Square root 100

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Harkirat
 3 years ago
Best ResponseYou've already chosen the best response.2????????? why don't u use the equation box to write yr question...

Maddiie
 3 years ago
Best ResponseYou've already chosen the best response.2In a paragraph, describe how to simplify each expression. 16 1/2 \[\sqrt{100}\]

Harkirat
 3 years ago
Best ResponseYou've already chosen the best response.2is the first one \[16^{1/2}\] ???

Harkirat
 3 years ago
Best ResponseYou've already chosen the best response.2pls note that \[x ^{1/2} = \sqrt{x}\]

Harkirat
 3 years ago
Best ResponseYou've already chosen the best response.2okay I will explain thru an example...

Harkirat
 3 years ago
Best ResponseYou've already chosen the best response.2u know that \[\sqrt{4}= 2\] also \[(4)^{1/2} = (2^{2})^{1/2} = 2^{2*1/2} = 2^{1}=2\]

Harkirat
 3 years ago
Best ResponseYou've already chosen the best response.2so we find that \[\sqrt{4} = (4)^{1/2}\] because both give same result i.e. 2

Harkirat
 3 years ago
Best ResponseYou've already chosen the best response.2so we can solve the first one as \[(16)^{1/2} = (4^{2})^{1/2} = 4^{2*1/2} = 4^{1}=4\]

Harkirat
 3 years ago
Best ResponseYou've already chosen the best response.2what is confusing u???

Maddiie
 3 years ago
Best ResponseYou've already chosen the best response.2Oh because 4x4=16 right

heromiles
 3 years ago
Best ResponseYou've already chosen the best response.0You might want to introduce and include rules of exponents and roots as part of your explanation.

Maddiie
 3 years ago
Best ResponseYou've already chosen the best response.2ok i understood the steps now

Maddiie
 3 years ago
Best ResponseYou've already chosen the best response.2ok i understood the steps now

Harkirat
 3 years ago
Best ResponseYou've already chosen the best response.2see square and root are opposite operations. so when they occur together, they cancel each other out.... we can show the working for root100 as follows : \[\sqrt{100}=\sqrt{10^{2}}=10\] the square inside and root outside cancel each other out

Harkirat
 3 years ago
Best ResponseYou've already chosen the best response.2are u familiar with exponential laws???

Maddiie
 3 years ago
Best ResponseYou've already chosen the best response.2not really but i can try to find it in my book

Harkirat
 3 years ago
Best ResponseYou've already chosen the best response.2yes, u shud have all the laws in front of you and slowly try to learn them by heart....

Harkirat
 3 years ago
Best ResponseYou've already chosen the best response.2u r welcome, just keep in mind... \[\sqrt{x}=x ^{1/2}\] \[\sqrt[3]{x}=x ^{1/3}\] \[\sqrt[4]{x}=x ^{1/4}\] and so on....
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