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In a paragraph, describe how to simplify each expression.
16 1/2
Square root 100
 2 years ago
 2 years ago
In a paragraph, describe how to simplify each expression. 16 1/2 Square root 100
 2 years ago
 2 years ago

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HarkiratBest ResponseYou've already chosen the best response.2
????????? why don't u use the equation box to write yr question...
 2 years ago

MaddiieBest ResponseYou've already chosen the best response.2
In a paragraph, describe how to simplify each expression. 16 1/2 \[\sqrt{100}\]
 2 years ago

HarkiratBest ResponseYou've already chosen the best response.2
is the first one \[16^{1/2}\] ???
 2 years ago

HarkiratBest ResponseYou've already chosen the best response.2
pls note that \[x ^{1/2} = \sqrt{x}\]
 2 years ago

HarkiratBest ResponseYou've already chosen the best response.2
okay I will explain thru an example...
 2 years ago

HarkiratBest ResponseYou've already chosen the best response.2
u know that \[\sqrt{4}= 2\] also \[(4)^{1/2} = (2^{2})^{1/2} = 2^{2*1/2} = 2^{1}=2\]
 2 years ago

HarkiratBest ResponseYou've already chosen the best response.2
so we find that \[\sqrt{4} = (4)^{1/2}\] because both give same result i.e. 2
 2 years ago

HarkiratBest ResponseYou've already chosen the best response.2
so we can solve the first one as \[(16)^{1/2} = (4^{2})^{1/2} = 4^{2*1/2} = 4^{1}=4\]
 2 years ago

HarkiratBest ResponseYou've already chosen the best response.2
what is confusing u???
 2 years ago

MaddiieBest ResponseYou've already chosen the best response.2
Oh because 4x4=16 right
 2 years ago

heromilesBest ResponseYou've already chosen the best response.0
You might want to introduce and include rules of exponents and roots as part of your explanation.
 2 years ago

MaddiieBest ResponseYou've already chosen the best response.2
ok i understood the steps now
 2 years ago

MaddiieBest ResponseYou've already chosen the best response.2
ok i understood the steps now
 2 years ago

HarkiratBest ResponseYou've already chosen the best response.2
see square and root are opposite operations. so when they occur together, they cancel each other out.... we can show the working for root100 as follows : \[\sqrt{100}=\sqrt{10^{2}}=10\] the square inside and root outside cancel each other out
 2 years ago

HarkiratBest ResponseYou've already chosen the best response.2
are u familiar with exponential laws???
 2 years ago

MaddiieBest ResponseYou've already chosen the best response.2
not really but i can try to find it in my book
 2 years ago

HarkiratBest ResponseYou've already chosen the best response.2
yes, u shud have all the laws in front of you and slowly try to learn them by heart....
 2 years ago

HarkiratBest ResponseYou've already chosen the best response.2
u r welcome, just keep in mind... \[\sqrt{x}=x ^{1/2}\] \[\sqrt[3]{x}=x ^{1/3}\] \[\sqrt[4]{x}=x ^{1/4}\] and so on....
 2 years ago
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