Maddiie 4 years ago In a paragraph, describe how to simplify each expression. 16 1/2 Square root 100

1. Harkirat

????????? why don't u use the equation box to write yr question...

In a paragraph, describe how to simplify each expression. 16 1/2 $\sqrt{100}$

3. Harkirat

is the first one $16^{1/2}$ ???

yes

5. Harkirat

pls note that $x ^{1/2} = \sqrt{x}$

why is that

7. Harkirat

okay I will explain thru an example...

ok awesome

9. Harkirat

u know that $\sqrt{4}= 2$ also $(4)^{1/2} = (2^{2})^{1/2} = 2^{2*1/2} = 2^{1}=2$

10. Harkirat

so we find that $\sqrt{4} = (4)^{1/2}$ because both give same result i.e. 2

$({8}^2)$

confused

13. Harkirat

so we can solve the first one as $(16)^{1/2} = (4^{2})^{1/2} = 4^{2*1/2} = 4^{1}=4$

14. Harkirat

what is confusing u???

Oh because 4x4=16 right

16. Harkirat

yes

So $\sqrt{100}= 10$

18. heromiles

You might want to introduce and include rules of exponents and roots as part of your explanation.

19. Harkirat

yes that is correct

ok i understood the steps now

ok i understood the steps now

22. Harkirat

see square and root are opposite operations. so when they occur together, they cancel each other out.... we can show the working for root100 as follows : $\sqrt{100}=\sqrt{10^{2}}=10$ the square inside and root outside cancel each other out

23. Harkirat

are u familiar with exponential laws???

makes sense

not really but i can try to find it in my book

26. Harkirat

yes, u shud have all the laws in front of you and slowly try to learn them by heart....

ok thank u

28. Harkirat

u r welcome, just keep in mind... $\sqrt{x}=x ^{1/2}$ $\sqrt[3]{x}=x ^{1/3}$ $\sqrt[4]{x}=x ^{1/4}$ and so on....