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Maddiie Group Title In a paragraph, describe how to simplify each expression. 16 1/2 Square root 100 3 years ago 3 years ago

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1. Harkirat Group Title

????????? why don't u use the equation box to write yr question...

2. Maddiie Group Title

In a paragraph, describe how to simplify each expression. 16 1/2 $\sqrt{100}$

3. Harkirat Group Title

is the first one $16^{1/2}$ ???

4. Maddiie Group Title

yes

5. Harkirat Group Title

pls note that $x ^{1/2} = \sqrt{x}$

6. Maddiie Group Title

why is that

7. Harkirat Group Title

okay I will explain thru an example...

8. Maddiie Group Title

ok awesome

9. Harkirat Group Title

u know that $\sqrt{4}= 2$ also $(4)^{1/2} = (2^{2})^{1/2} = 2^{2*1/2} = 2^{1}=2$

10. Harkirat Group Title

so we find that $\sqrt{4} = (4)^{1/2}$ because both give same result i.e. 2

11. Maddiie Group Title

$({8}^2)$

12. Maddiie Group Title

confused

13. Harkirat Group Title

so we can solve the first one as $(16)^{1/2} = (4^{2})^{1/2} = 4^{2*1/2} = 4^{1}=4$

14. Harkirat Group Title

what is confusing u???

15. Maddiie Group Title

Oh because 4x4=16 right

16. Harkirat Group Title

yes

17. Maddiie Group Title

So $\sqrt{100}= 10$

18. heromiles Group Title

You might want to introduce and include rules of exponents and roots as part of your explanation.

19. Harkirat Group Title

yes that is correct

20. Maddiie Group Title

ok i understood the steps now

21. Maddiie Group Title

ok i understood the steps now

22. Harkirat Group Title

see square and root are opposite operations. so when they occur together, they cancel each other out.... we can show the working for root100 as follows : $\sqrt{100}=\sqrt{10^{2}}=10$ the square inside and root outside cancel each other out

23. Harkirat Group Title

are u familiar with exponential laws???

24. Maddiie Group Title

makes sense

25. Maddiie Group Title

not really but i can try to find it in my book

26. Harkirat Group Title

yes, u shud have all the laws in front of you and slowly try to learn them by heart....

27. Maddiie Group Title

ok thank u

28. Harkirat Group Title

u r welcome, just keep in mind... $\sqrt{x}=x ^{1/2}$ $\sqrt[3]{x}=x ^{1/3}$ $\sqrt[4]{x}=x ^{1/4}$ and so on....