6. Jack and Jane are initially separated by a distance of 160 m.
a) If Jack and Jane starts to move towards each other with a speed of 1 m/s at the same time, how long would it take for them to meet at the same position?
Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
May i know how did you get the answer ? thank you.
since they have the same rate/ you can conclude that they will meet at a point wherebthey have equal distances. That makes their distance both 80m. Since they can move 1 mile per second, 80 miles would be 80 seconds. :)
Not the answer you are looking for? Search for more explanations.
Does that answer your question??
Yes. Thank you very much :)
u can use relative motion.they are coming toward each other so u can sum their rates.1+1=2m/s now u can find the time bye the equation X=VT which tends to 160=2t.solving for t u have T=8O. u can find the distance bye multiplying 80*1=80m
around 42 parsecs. Give or take 2 drizzles, but make sure to convert from swizzles first.