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6. Jack and Jane are initially separated by a distance of 160 m.
a) If Jack and Jane starts to move towards each other with a speed of 1 m/s at the same time, how long would it take for them to meet at the same position?
 2 years ago
 2 years ago
6. Jack and Jane are initially separated by a distance of 160 m. a) If Jack and Jane starts to move towards each other with a speed of 1 m/s at the same time, how long would it take for them to meet at the same position?
 2 years ago
 2 years ago

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greenteafrapppBest ResponseYou've already chosen the best response.0
May i know how did you get the answer ? thank you.
 2 years ago

josephniel14Best ResponseYou've already chosen the best response.0
since they have the same rate/ you can conclude that they will meet at a point wherebthey have equal distances. That makes their distance both 80m. Since they can move 1 mile per second, 80 miles would be 80 seconds. :)
 2 years ago

josephniel14Best ResponseYou've already chosen the best response.0
Does that answer your question??
 2 years ago

greenteafrapppBest ResponseYou've already chosen the best response.0
Yes. Thank you very much :)
 2 years ago

ARASH_DBest ResponseYou've already chosen the best response.1
u can use relative motion.they are coming toward each other so u can sum their rates.1+1=2m/s now u can find the time bye the equation X=VT which tends to 160=2t.solving for t u have T=8O. u can find the distance bye multiplying 80*1=80m
 2 years ago

waterfallingBest ResponseYou've already chosen the best response.0
around 42 parsecs. Give or take 2 drizzles, but make sure to convert from swizzles first.
 2 years ago

the_dukeBest ResponseYou've already chosen the best response.0
arash d gave a very good solution.
 2 years ago
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