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greenteafrappp

6. Jack and Jane are initially separated by a distance of 160 m. a) If Jack and Jane starts to move towards each other with a speed of 1 m/s at the same time, how long would it take for them to meet at the same position?

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  1. josephniel14
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    80s

    • 2 years ago
  2. greenteafrappp
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    May i know how did you get the answer ? thank you.

    • 2 years ago
  3. josephniel14
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    since they have the same rate/ you can conclude that they will meet at a point wherebthey have equal distances. That makes their distance both 80m. Since they can move 1 mile per second, 80 miles would be 80 seconds. :)

    • 2 years ago
  4. josephniel14
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    Does that answer your question??

    • 2 years ago
  5. greenteafrappp
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    Yes. Thank you very much :)

    • 2 years ago
  6. ARASH_D
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    u can use relative motion.they are coming toward each other so u can sum their rates.1+1=2m/s now u can find the time bye the equation X=VT which tends to 160=2t.solving for t u have T=8O. u can find the distance bye multiplying 80*1=80m

    • 2 years ago
  7. waterfalling
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    around 42 parsecs. Give or take 2 drizzles, but make sure to convert from swizzles first.

    • 2 years ago
  8. the_duke
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    arash d gave a very good solution.

    • 2 years ago
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