Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

chris_parks

  • 4 years ago

In a 30-60-90 triangle, the hypotenuse is 20 feet long. Find the length of the length of the long leg and the short leg

  • This Question is Closed
  1. josephniel14
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    short - 10 long - \[10\sqrt{3}\]

  2. anonymous
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    short leg is half of the hypotenuse

  3. josephniel14
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    :))

  4. Sriram
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    20cos60=10 and 20sin60=10 *(30)^1/2

  5. josephniel14
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    @siriam: LOLwut?

  6. josephniel14
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    You can just use some formulas because the given is a special triangle.

  7. anonymous
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    you need to trig for this. short side is half of long side because it is half of an equilateral triangle then the other side comes from pythagoras.

  8. anonymous
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i meant you need NO trig

  9. Sriram
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    dude 20/short side=cos60 & 20 / long side=sin60 whats wrong in it??

  10. Khu052
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    there's nothing wrong with it, it's just the harder option.

  11. josephniel14
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Nothing. You can just use simple equations for special triangles.

  12. anonymous
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    nothing wrong except that the only reason you know the cosine of 60 degrees is because you know the ratios, not the other way around!

  13. ARASH_D
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    short=20*sin30=10 long=20*sin60=10\[\sqrt{3}\]

  14. josephniel14
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Why are you applying trigonometry on such easy questions?

  15. josephniel14
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    You can just use simple equations on special triangles.

  16. josephniel14
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    in a 30-60-90, a = short side, b = long side, c = hypotenuse c = 2a ; b = \[ a \sqrt{3}\]

  17. ARASH_D
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i think u did it too.i have no problem with trigonometry

  18. robtobey
    • 4 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \[\text{long} \text{side}=20\text{Cos}\left[\text{ArcSin}\left[\frac{10}{20}\right]\right]=10 \sqrt{3} \]\[20^2=10^2+\left(10 \sqrt{3}\right)^2, 400=100+300, 400= 400 \]

  19. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy