## chris_parks Group Title In a 30-60-90 triangle, the hypotenuse is 20 feet long. Find the length of the length of the long leg and the short leg 3 years ago 3 years ago

1. josephniel14 Group Title

short - 10 long - $10\sqrt{3}$

2. satellite73 Group Title

short leg is half of the hypotenuse

3. josephniel14 Group Title

:))

4. Sriram Group Title

20cos60=10 and 20sin60=10 *(30)^1/2

5. josephniel14 Group Title

@siriam: LOLwut?

6. josephniel14 Group Title

You can just use some formulas because the given is a special triangle.

7. satellite73 Group Title

you need to trig for this. short side is half of long side because it is half of an equilateral triangle then the other side comes from pythagoras.

8. satellite73 Group Title

i meant you need NO trig

9. Sriram Group Title

dude 20/short side=cos60 & 20 / long side=sin60 whats wrong in it??

10. Khu052 Group Title

there's nothing wrong with it, it's just the harder option.

11. josephniel14 Group Title

Nothing. You can just use simple equations for special triangles.

12. satellite73 Group Title

nothing wrong except that the only reason you know the cosine of 60 degrees is because you know the ratios, not the other way around!

13. ARASH_D Group Title

short=20*sin30=10 long=20*sin60=10$\sqrt{3}$

14. josephniel14 Group Title

Why are you applying trigonometry on such easy questions?

15. josephniel14 Group Title

You can just use simple equations on special triangles.

16. josephniel14 Group Title

in a 30-60-90, a = short side, b = long side, c = hypotenuse c = 2a ; b = $a \sqrt{3}$

17. ARASH_D Group Title

i think u did it too.i have no problem with trigonometry

18. robtobey Group Title

$\text{long} \text{side}=20\text{Cos}\left[\text{ArcSin}\left[\frac{10}{20}\right]\right]=10 \sqrt{3}$$20^2=10^2+\left(10 \sqrt{3}\right)^2, 400=100+300, 400= 400$