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In a 306090 triangle, the hypotenuse is 20 feet long. Find the length of the length of the long leg and the short leg
 2 years ago
 2 years ago
In a 306090 triangle, the hypotenuse is 20 feet long. Find the length of the length of the long leg and the short leg
 2 years ago
 2 years ago

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josephniel14Best ResponseYou've already chosen the best response.1
short  10 long  \[10\sqrt{3}\]
 2 years ago

satellite73Best ResponseYou've already chosen the best response.1
short leg is half of the hypotenuse
 2 years ago

SriramBest ResponseYou've already chosen the best response.0
20cos60=10 and 20sin60=10 *(30)^1/2
 2 years ago

josephniel14Best ResponseYou've already chosen the best response.1
You can just use some formulas because the given is a special triangle.
 2 years ago

satellite73Best ResponseYou've already chosen the best response.1
you need to trig for this. short side is half of long side because it is half of an equilateral triangle then the other side comes from pythagoras.
 2 years ago

satellite73Best ResponseYou've already chosen the best response.1
i meant you need NO trig
 2 years ago

SriramBest ResponseYou've already chosen the best response.0
dude 20/short side=cos60 & 20 / long side=sin60 whats wrong in it??
 2 years ago

Khu052Best ResponseYou've already chosen the best response.0
there's nothing wrong with it, it's just the harder option.
 2 years ago

josephniel14Best ResponseYou've already chosen the best response.1
Nothing. You can just use simple equations for special triangles.
 2 years ago

satellite73Best ResponseYou've already chosen the best response.1
nothing wrong except that the only reason you know the cosine of 60 degrees is because you know the ratios, not the other way around!
 2 years ago

ARASH_DBest ResponseYou've already chosen the best response.0
short=20*sin30=10 long=20*sin60=10\[\sqrt{3}\]
 2 years ago

josephniel14Best ResponseYou've already chosen the best response.1
Why are you applying trigonometry on such easy questions?
 2 years ago

josephniel14Best ResponseYou've already chosen the best response.1
You can just use simple equations on special triangles.
 2 years ago

josephniel14Best ResponseYou've already chosen the best response.1
in a 306090, a = short side, b = long side, c = hypotenuse c = 2a ; b = \[ a \sqrt{3}\]
 2 years ago

ARASH_DBest ResponseYou've already chosen the best response.0
i think u did it too.i have no problem with trigonometry
 2 years ago

robtobeyBest ResponseYou've already chosen the best response.0
\[\text{long} \text{side}=20\text{Cos}\left[\text{ArcSin}\left[\frac{10}{20}\right]\right]=10 \sqrt{3} \]\[20^2=10^2+\left(10 \sqrt{3}\right)^2, 400=100+300, 400= 400 \]
 2 years ago
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