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anonymous
 4 years ago
In a 306090 triangle, the hypotenuse is 20 feet long. Find the length of the length of the long leg and the short leg
anonymous
 4 years ago
In a 306090 triangle, the hypotenuse is 20 feet long. Find the length of the length of the long leg and the short leg

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0short  10 long  \[10\sqrt{3}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0short leg is half of the hypotenuse

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.020cos60=10 and 20sin60=10 *(30)^1/2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0You can just use some formulas because the given is a special triangle.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you need to trig for this. short side is half of long side because it is half of an equilateral triangle then the other side comes from pythagoras.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i meant you need NO trig

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dude 20/short side=cos60 & 20 / long side=sin60 whats wrong in it??

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0there's nothing wrong with it, it's just the harder option.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Nothing. You can just use simple equations for special triangles.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0nothing wrong except that the only reason you know the cosine of 60 degrees is because you know the ratios, not the other way around!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0short=20*sin30=10 long=20*sin60=10\[\sqrt{3}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Why are you applying trigonometry on such easy questions?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0You can just use simple equations on special triangles.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0in a 306090, a = short side, b = long side, c = hypotenuse c = 2a ; b = \[ a \sqrt{3}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i think u did it too.i have no problem with trigonometry

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\text{long} \text{side}=20\text{Cos}\left[\text{ArcSin}\left[\frac{10}{20}\right]\right]=10 \sqrt{3} \]\[20^2=10^2+\left(10 \sqrt{3}\right)^2, 400=100+300, 400= 400 \]
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