Here's the question you clicked on:
chris_parks
In a 30-60-90 triangle, the hypotenuse is 20 feet long. Find the length of the length of the long leg and the short leg
short - 10 long - \[10\sqrt{3}\]
short leg is half of the hypotenuse
20cos60=10 and 20sin60=10 *(30)^1/2
You can just use some formulas because the given is a special triangle.
you need to trig for this. short side is half of long side because it is half of an equilateral triangle then the other side comes from pythagoras.
i meant you need NO trig
dude 20/short side=cos60 & 20 / long side=sin60 whats wrong in it??
there's nothing wrong with it, it's just the harder option.
Nothing. You can just use simple equations for special triangles.
nothing wrong except that the only reason you know the cosine of 60 degrees is because you know the ratios, not the other way around!
short=20*sin30=10 long=20*sin60=10\[\sqrt{3}\]
Why are you applying trigonometry on such easy questions?
You can just use simple equations on special triangles.
in a 30-60-90, a = short side, b = long side, c = hypotenuse c = 2a ; b = \[ a \sqrt{3}\]
i think u did it too.i have no problem with trigonometry
\[\text{long} \text{side}=20\text{Cos}\left[\text{ArcSin}\left[\frac{10}{20}\right]\right]=10 \sqrt{3} \]\[20^2=10^2+\left(10 \sqrt{3}\right)^2, 400=100+300, 400= 400 \]