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anonymous
 4 years ago
sin 17 = a
so, cot 253+csc253 = ?
anonymous
 4 years ago
sin 17 = a so, cot 253+csc253 = ?

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the choice is a. (a1)/sqrt(1a^2) b. (1a) / sqrt (1a^2) c. (a1)/sqrt(a^21) d. (1a) / sqrt (a^21) e. (a1) / sqrt (1a^2)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0(cos253+1)/sin253=(1+cos270cos17+sin270sin17)/(sin270in17cos270cos17)=(1a)/(a)=11/a

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0the answer is b. (1a)/sqrt(1a^2) sin 17=a > cos 253=cos 73=a. Furthermore, cot 253 + csc 253 = (cos 253+1)/sin253 hence the answer

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Notice that 270  253 = 17, so sin (17) = cos (253) cot 253 + csc 253 = [cos(253)/sin(253)] + 1/sin(253) = [cos (253) + 1]/sin(253) but cos(253) = a so: 1a/sin(253) from the numerator, we know only b or d could be correct. Looking at the denominator, sin(253), we can use the trigonometric identity: sin^2(x) + cos^2(x) = 1 Thus, sin(253) = sqrt[sin^2(253)] = sqrt[1cos^2(253)] and cos(253) is a, so the denominator is sqrt(1a^2) The end equation is 1a/sqrt(1a^2) B is the correct answer
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