A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 5 years ago
sin 17 = a
so, cot 253+csc253 = ?
anonymous
 5 years ago
sin 17 = a so, cot 253+csc253 = ?

This Question is Closed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the choice is a. (a1)/sqrt(1a^2) b. (1a) / sqrt (1a^2) c. (a1)/sqrt(a^21) d. (1a) / sqrt (a^21) e. (a1) / sqrt (1a^2)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0(cos253+1)/sin253=(1+cos270cos17+sin270sin17)/(sin270in17cos270cos17)=(1a)/(a)=11/a

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the answer is b. (1a)/sqrt(1a^2) sin 17=a > cos 253=cos 73=a. Furthermore, cot 253 + csc 253 = (cos 253+1)/sin253 hence the answer

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Notice that 270  253 = 17, so sin (17) = cos (253) cot 253 + csc 253 = [cos(253)/sin(253)] + 1/sin(253) = [cos (253) + 1]/sin(253) but cos(253) = a so: 1a/sin(253) from the numerator, we know only b or d could be correct. Looking at the denominator, sin(253), we can use the trigonometric identity: sin^2(x) + cos^2(x) = 1 Thus, sin(253) = sqrt[sin^2(253)] = sqrt[1cos^2(253)] and cos(253) is a, so the denominator is sqrt(1a^2) The end equation is 1a/sqrt(1a^2) B is the correct answer
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.