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heromiles
 3 years ago
Best ResponseYou've already chosen the best response.0multiply both sides by the denominator

amogh
 3 years ago
Best ResponseYou've already chosen the best response.2you cannot do that as 1x can be negative, You can do that be wavy curve method, Or common sense, If a ratio has to be +ve, both numerator n denominator have to be of the same sign, 1+x >0 , x>1 1x >0 , x<1 common soln. (1,1) 1+x<0 , x<1 1x<0 , x>1 common soln. (nothing!) Therefore, the ans is (1,1)

joemath314159
 3 years ago
Best ResponseYou've already chosen the best response.0if you multiply both sides by the denominator you would get 1 + x > 0(1  x) which is 1 +x > 0

heromiles
 3 years ago
Best ResponseYou've already chosen the best response.0For some reason, I have to do this on paper, not in my head

satellite73
 3 years ago
Best ResponseYou've already chosen the best response.0you cannot multiply both sides by a variable in an inequality

amogh
 3 years ago
Best ResponseYou've already chosen the best response.2@satellite: you can if you know that its gonna be +ve or ve

Alexis1994_13
 3 years ago
Best ResponseYou've already chosen the best response.0I guess amogh it's right. Thanks guys.

satellite73
 3 years ago
Best ResponseYou've already chosen the best response.0your answer is all numbers between 1 and 1 i.e. (1,1)

joemath314159
 3 years ago
Best ResponseYou've already chosen the best response.0Satellite and amogh have the right idea.

heromiles
 3 years ago
Best ResponseYou've already chosen the best response.0I neglected to use critical points and the intervals between them

satellite73
 3 years ago
Best ResponseYou've already chosen the best response.0and it is easy enough to solve. for one thing you can just think of \[(1+x)(1x)> 0\] which is a parabola facing down. therefore it is positive between the zeros and negative outside of them. the zeros are 1 and 1 so it is positive between those two numbers and negative outside of them

Alexis1994_13
 3 years ago
Best ResponseYou've already chosen the best response.0Very usefull site! Thank ya all :)

satellite73
 3 years ago
Best ResponseYou've already chosen the best response.0or you can say you have two factors , 1+x which is positive if x > 1 negative for x < 1 1x which is positive if x < 1 and negative is x > 1 then what happens when you divide? if you are between 1 and 1 both are positive, and so the quotient will be as well
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