anonymous
  • anonymous
(1+x)/(1-x)>0 What's next? :S
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
multiply both sides by the denominator
anonymous
  • anonymous
you cannot do that as 1-x can be negative, You can do that be wavy curve method, Or common sense, If a ratio has to be +ve, both numerator n denominator have to be of the same sign, 1+x >0 , x>-1 1-x >0 , x<1 common soln. (-1,1) 1+x<0 , x<-1 1-x<0 , x>1 common soln. (nothing!) Therefore, the ans is (-1,1)
anonymous
  • anonymous
if you multiply both sides by the denominator you would get 1 + x > 0(1 - x) which is 1 +x > 0

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More answers

anonymous
  • anonymous
For some reason, I have to do this on paper, not in my head
anonymous
  • anonymous
you cannot multiply both sides by a variable in an inequality
anonymous
  • anonymous
@satellite: you can if you know that its gonna be +ve or -ve
anonymous
  • anonymous
I guess amogh it's right. Thanks guys.
anonymous
  • anonymous
np
anonymous
  • anonymous
??
anonymous
  • anonymous
your answer is all numbers between -1 and 1 i.e. (-1,1)
anonymous
  • anonymous
Okay, I give up
anonymous
  • anonymous
Satellite and amogh have the right idea.
anonymous
  • anonymous
f(x) ε (-1,1)
anonymous
  • anonymous
I neglected to use critical points and the intervals between them
anonymous
  • anonymous
and it is easy enough to solve. for one thing you can just think of \[(1+x)(1-x)> 0\] which is a parabola facing down. therefore it is positive between the zeros and negative outside of them. the zeros are -1 and 1 so it is positive between those two numbers and negative outside of them
anonymous
  • anonymous
Very usefull site! Thank ya all :)
anonymous
  • anonymous
or you can say you have two factors , 1+x which is positive if x > -1 negative for x < -1 1-x which is positive if x < 1 and negative is x > 1 then what happens when you divide? if you are between -1 and 1 both are positive, and so the quotient will be as well

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