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heromiles Group TitleBest ResponseYou've already chosen the best response.0
multiply both sides by the denominator
 3 years ago

amogh Group TitleBest ResponseYou've already chosen the best response.2
you cannot do that as 1x can be negative, You can do that be wavy curve method, Or common sense, If a ratio has to be +ve, both numerator n denominator have to be of the same sign, 1+x >0 , x>1 1x >0 , x<1 common soln. (1,1) 1+x<0 , x<1 1x<0 , x>1 common soln. (nothing!) Therefore, the ans is (1,1)
 3 years ago

joemath314159 Group TitleBest ResponseYou've already chosen the best response.0
if you multiply both sides by the denominator you would get 1 + x > 0(1  x) which is 1 +x > 0
 3 years ago

heromiles Group TitleBest ResponseYou've already chosen the best response.0
For some reason, I have to do this on paper, not in my head
 3 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
you cannot multiply both sides by a variable in an inequality
 3 years ago

amogh Group TitleBest ResponseYou've already chosen the best response.2
@satellite: you can if you know that its gonna be +ve or ve
 3 years ago

Alexis1994_13 Group TitleBest ResponseYou've already chosen the best response.0
I guess amogh it's right. Thanks guys.
 3 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
your answer is all numbers between 1 and 1 i.e. (1,1)
 3 years ago

heromiles Group TitleBest ResponseYou've already chosen the best response.0
Okay, I give up
 3 years ago

joemath314159 Group TitleBest ResponseYou've already chosen the best response.0
Satellite and amogh have the right idea.
 3 years ago

Alexis1994_13 Group TitleBest ResponseYou've already chosen the best response.0
f(x) ε (1,1)
 3 years ago

heromiles Group TitleBest ResponseYou've already chosen the best response.0
I neglected to use critical points and the intervals between them
 3 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
and it is easy enough to solve. for one thing you can just think of \[(1+x)(1x)> 0\] which is a parabola facing down. therefore it is positive between the zeros and negative outside of them. the zeros are 1 and 1 so it is positive between those two numbers and negative outside of them
 3 years ago

Alexis1994_13 Group TitleBest ResponseYou've already chosen the best response.0
Very usefull site! Thank ya all :)
 3 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.0
or you can say you have two factors , 1+x which is positive if x > 1 negative for x < 1 1x which is positive if x < 1 and negative is x > 1 then what happens when you divide? if you are between 1 and 1 both are positive, and so the quotient will be as well
 3 years ago
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