## mlhuyck Group Title solve | y + 2 |> 6 3 years ago 3 years ago

1. Alexis1994_13 Group Title

-6>v+2>6

2. Alexis1994_13 Group Title

-6-2>v+2-2>6-2

3. Alexis1994_13 Group Title

Finally we have, -8>v>4

4. satellite73 Group Title

ok i give up. go ahead. but i am going to say it again anyway. there is not such thing as $-6>blah>6$ because there is nothing that is less than -6 and at the same time greater than 6

5. satellite73 Group Title

your answer will contain TWO intervals and you have to write TWO inequalities. they are : $y+2<-6$ OR $Y+2>6$

6. Alexis1994_13 Group Title

OMG!,What am I writing ??????

7. satellite73 Group Title

you solve them separately, not at one time. you get $y+2<-6$ $y<-8$ OR $y+2>6$ $y>4$ and your answers are $y<-8 \text{ OR } y>4$ or in interval notation $(-\infty,-8) \cup (4,\infty)$

8. satellite73 Group Title

@alexis at least you recognized the mistake. in the last post someone thought you could make this "easier" by solving them at the same time!

9. Alexis1994_13 Group Title

haha,lol. It's a mistake that I am doing usually I can say. :p