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mlhuyck

  • 4 years ago

solve | y + 2 |> 6

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  1. Alexis1994_13
    • 4 years ago
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    -6>v+2>6

  2. Alexis1994_13
    • 4 years ago
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    -6-2>v+2-2>6-2

  3. Alexis1994_13
    • 4 years ago
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    Finally we have, -8>v>4

  4. satellite73
    • 4 years ago
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    ok i give up. go ahead. but i am going to say it again anyway. there is not such thing as \[-6>blah>6\] because there is nothing that is less than -6 and at the same time greater than 6

  5. satellite73
    • 4 years ago
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    your answer will contain TWO intervals and you have to write TWO inequalities. they are : \[y+2<-6\] OR \[Y+2>6\]

  6. Alexis1994_13
    • 4 years ago
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    OMG!,What am I writing ??????

  7. satellite73
    • 4 years ago
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    you solve them separately, not at one time. you get \[y+2<-6\] \[y<-8\] OR \[y+2>6\] \[y>4\] and your answers are \[y<-8 \text{ OR } y>4\] or in interval notation \[(-\infty,-8) \cup (4,\infty)\]

  8. satellite73
    • 4 years ago
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    @alexis at least you recognized the mistake. in the last post someone thought you could make this "easier" by solving them at the same time!

  9. Alexis1994_13
    • 4 years ago
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    haha,lol. It's a mistake that I am doing usually I can say. :p

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