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Alexis1994_13Best ResponseYou've already chosen the best response.2
Finally we have, 8>v>4
 2 years ago

satellite73Best ResponseYou've already chosen the best response.0
ok i give up. go ahead. but i am going to say it again anyway. there is not such thing as \[6>blah>6\] because there is nothing that is less than 6 and at the same time greater than 6
 2 years ago

satellite73Best ResponseYou've already chosen the best response.0
your answer will contain TWO intervals and you have to write TWO inequalities. they are : \[y+2<6\] OR \[Y+2>6\]
 2 years ago

Alexis1994_13Best ResponseYou've already chosen the best response.2
OMG!,What am I writing ??????
 2 years ago

satellite73Best ResponseYou've already chosen the best response.0
you solve them separately, not at one time. you get \[y+2<6\] \[y<8\] OR \[y+2>6\] \[y>4\] and your answers are \[y<8 \text{ OR } y>4\] or in interval notation \[(\infty,8) \cup (4,\infty)\]
 2 years ago

satellite73Best ResponseYou've already chosen the best response.0
@alexis at least you recognized the mistake. in the last post someone thought you could make this "easier" by solving them at the same time!
 2 years ago

Alexis1994_13Best ResponseYou've already chosen the best response.2
haha,lol. It's a mistake that I am doing usually I can say. :p
 2 years ago
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