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Alexis1994_13

  • 4 years ago

f(x)=e^x + 1 A(x,y)? x=? , y=?

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  1. Alexis1994_13
    • 4 years ago
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    A(0,2) ?

  2. amistre64
    • 4 years ago
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    i cant really make out what the question is ..

  3. A_clan
    • 4 years ago
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    my solution is: Put random values of x in equation to obtain y-values.

  4. Alexis1994_13
    • 4 years ago
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    y=e^x+1 I need to found x and y. I need to put 0 on y once and once on x. But I am not sure if I have (0,2)

  5. A_clan
    • 4 years ago
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    (0,2) satisfies. It is a solution to equation.

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