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we have 2 vectors the differ by at most a scalar

AB*BC=0 ?

does dotting parallel vectors produce a 0? they aint orthogonal that I can recall

0,1
0,1
----
0+1 = 1
0,1
0,-1
----
0-1 = -1

3 , 4
-3,-4
-----
-9-12 = -18

AB+BC=-1 ?

adding vectors produces another vector, not a scalar

youre gonna have to provide more verbiage if I am to understand what it is your asking :)

that and 4.-4 = -16 ... not -12 lol

I mean,I need to find fot wich k those vectors are parallel.

when they differ by only a scalar; by a multiplicative factor.
2 = 2k-2
and
6 = 5k-4

You could test values of k--

4 = 2k; k=2
10 = 5k; k=2
right? so when k=2; that is one possible option for parallel

then we have AB//BC <=> AB = BC

when ab = bc; they are parallel; but thats not the only case ...

normal to one is normal to the other...

okay,I got it :D
Thank ya a lot.

2 , 6
2k-2, 5k-4
-----------
4k-4 + 30k-24 = 34k -28 ..... :)