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how would we start it?

5|χ+1|=15 => |x+1| = 3.

assuming x is real:
\[5 \sqrt((x+1)^2)+6 = 21\]
otherwise:
|x+1|=3

don't just give it to him.

i don't know how to start it absolute value i just don't understand it

the absolute value is the last thing to work on; how do you get that absolute value all by itself?

5(x+1)+6=21
(5x+5)+6=21
5x+6=16
5x=10
x=2

looking at this question, what is the other solution for x if it was not an absolute value?

i'm seriously terrible in math i really don't know:[

dont jus give him the answer he is probably usin this site for a summer school!!!

|a| is always positive, you discount the negative answer.

|-12| has the same absolute value as |12|

What do you get when you subtract the 6?

-2?

No,
\(5|x+1| + 6 - 6 = 21 -6\)
\[\implies 5|x+1| + 0 = 15\]\[\implies 5|x+1| = 15\]

I am assuming the other answer is x=-4

x =-4 is one solution yes, because
|-4 + 1 | = |-3| = 3