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amistre64 Group TitleBest ResponseYou've already chosen the best response.0
how would we start it?
 3 years ago

Alexis1994_13 Group TitleBest ResponseYou've already chosen the best response.0
5χ+1=15 => x+1 = 3.
 3 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.0
im sure as long as you just get an answer; you will continue to type in the same kind of problem over and over again :)
 3 years ago

Llort Group TitleBest ResponseYou've already chosen the best response.0
assuming x is real: \[5 \sqrt((x+1)^2)+6 = 21\] otherwise: x+1=3
 3 years ago

Llort Group TitleBest ResponseYou've already chosen the best response.0
don't just give it to him.
 3 years ago

skyhimself75 Group TitleBest ResponseYou've already chosen the best response.0
i don't know how to start it absolute value i just don't understand it
 3 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.0
the absolute value is the last thing to work on; how do you get that absolute value all by itself?
 3 years ago

rauch Group TitleBest ResponseYou've already chosen the best response.0
5(x+1)+6=21 (5x+5)+6=21 5x+6=16 5x=10 x=2
 3 years ago

Llort Group TitleBest ResponseYou've already chosen the best response.0
looking at this question, what is the other solution for x if it was not an absolute value?
 3 years ago

skyhimself75 Group TitleBest ResponseYou've already chosen the best response.0
i'm seriously terrible in math i really don't know:[
 3 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.0
the term "absolute value" means that there is a quantifiable value; something that can be measured. length, height, area, volume, distance are all examples of abslute values
 3 years ago

jgeorge123 Group TitleBest ResponseYou've already chosen the best response.0
dont jus give him the answer he is probably usin this site for a summer school!!!
 3 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.0
in other words; an absolute value doesnt care about what direction the sign takes us in; it only cares about a quantifiable measure
 3 years ago

Llort Group TitleBest ResponseYou've already chosen the best response.0
a is always positive, you discount the negative answer.
 3 years ago

polpak Group TitleBest ResponseYou've already chosen the best response.0
sky, you isolate the absolute value just like you would isolate a variable. Llort, no you do not 'discount' the negative answer. It is a valid solution.
 3 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.0
12 has the same absolute value as 12
 3 years ago

amistre64 Group TitleBest ResponseYou've already chosen the best response.0
as a result; if we are determining any value for inside of the absolute value notation; we have to account for the positive and the negative results that occur within it
 3 years ago

polpak Group TitleBest ResponseYou've already chosen the best response.0
So if you have \[5x+1 + 6 = 21\] You want to isolate the term with the absolute value in it first. You do this by subtracting 6 from both sides of the equation.
 3 years ago

polpak Group TitleBest ResponseYou've already chosen the best response.0
What do you get when you subtract the 6?
 3 years ago

polpak Group TitleBest ResponseYou've already chosen the best response.0
No, \(5x+1 + 6  6 = 21 6\) \[\implies 5x+1 + 0 = 15\]\[\implies 5x+1 = 15\]
 3 years ago

polpak Group TitleBest ResponseYou've already chosen the best response.0
So now lets say that x+1 is something, lets call it k.. So we have \(5k = 15 \)\[\implies \frac{1}{5}\cdot5k = \frac{1}{5}15\]\[\implies k = 3\] And since we said k was x+1 we have \[x+1 = 3\]So what values can x have and still make this equation true?
 3 years ago

Llort Group TitleBest ResponseYou've already chosen the best response.0
I am assuming the other answer is x=4
 3 years ago

polpak Group TitleBest ResponseYou've already chosen the best response.0
x =4 is one solution yes, because 4 + 1  = 3 = 3
 3 years ago
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