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adebaworin

  • 4 years ago

Find the equation of a circle in standard form where C(6, -2) and D(-4, 4) are endpoints of a diameter.

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  1. anonymous
    • 4 years ago
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    first find the center, which is the middle of the two points. it is \[(\frac{6-4}{2},\frac{-2+4}{2})\] or \[(-1,1)\]

  2. anonymous
    • 4 years ago
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    dam i made a mistake. the center is not \[(-1,1)\] it is \[(1,1)\]

  3. anonymous
    • 4 years ago
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    bad arithmetic. now you need the radius from the distance formula \[r^2=(6-1)^2+(-2-1)^2=5^2+3^2=25-9=34\]

  4. anonymous
    • 4 years ago
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    so your equation is \[(x-1)^2+(y-1)^2=34\]

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