## anonymous 5 years ago Find the equation of a circle in standard form where C(6, -2) and D(-4, 4) are endpoints of a diameter.

1. anonymous

first find the center, which is the middle of the two points. it is $(\frac{6-4}{2},\frac{-2+4}{2})$ or $(-1,1)$

2. anonymous

dam i made a mistake. the center is not $(-1,1)$ it is $(1,1)$

3. anonymous

bad arithmetic. now you need the radius from the distance formula $r^2=(6-1)^2+(-2-1)^2=5^2+3^2=25-9=34$

4. anonymous

so your equation is $(x-1)^2+(y-1)^2=34$