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adebaworin

  • 4 years ago

Find the general form of the equation of the the circle. Center at the point (-4, -3); containing the point (-3, 3)

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  1. anonymous
    • 4 years ago
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    general form is \[(x-h)^2+(y-k)^2=r^2\] so you will have \[(x+4)^2+(y+3)^2=r^2\] and now you just need \[r^2\]

  2. anonymous
    • 4 years ago
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    to find it find the square of the distance between these point. i t is \[r^2=(-4+3)^2+(-3-3)^2=1+36=37\] so y our answer is \[(x+4)^2+(y+3)^2=37\]

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