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Alexis1994_13

  • 4 years ago

f(z)=(3*z+1)/(z+4*i) f(2+1)= ? Please help,I am founding fault result.

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  1. Thomas9
    • 4 years ago
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    f(3)=(3*3+1)/(3+4i)=10(3-4i)/25=6/5+4i/25

  2. joemath314159
    • 4 years ago
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    was it f(2+i) or f(2+1) = f(3)?

  3. Alexis1994_13
    • 4 years ago
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    Sorry! it's f(2+i)!

  4. myininaya
    • 4 years ago
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    factorial thats scary

  5. myininaya
    • 4 years ago
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    i know thats an exclamation mark

  6. myininaya
    • 4 years ago
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    \[f(2+i)=\frac{3(2+i)+1}{2+i+4i}\] what exactly do you want? you seem to be in upper level class so what should i write this as or i mean what is the goal

  7. joemath314159
    • 4 years ago
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    scanning solution now, answer in sec....then breakfast >.>

  8. myininaya
    • 4 years ago
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    im gonna have a fruit smoothie joe what state do you live in?

  9. joemath314159
    • 4 years ago
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    Texas (sadly)

  10. myininaya
    • 4 years ago
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    i live next door

  11. joemath314159
    • 4 years ago
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    solution, might be wrong, i think its right though. hunger has adverse effects on math.

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  12. myininaya
    • 4 years ago
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    so im sadder

  13. Alexis1994_13
    • 4 years ago
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    I am founding (7+3i)/(2+5i) but the answer is 1-i.

  14. joemath314159
    • 4 years ago
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    next door? Louisiana? i think thats spelled right

  15. myininaya
    • 4 years ago
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    no arkansas

  16. joemath314159
    • 4 years ago
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    LOL i added wrong. 14+15 is 29, not 39

  17. myininaya
    • 4 years ago
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    see we arent all hicks

  18. joemath314159
    • 4 years ago
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    you are on the right path alexis, you just need to get the complex number out of the denominator of that fraction.

  19. joemath314159
    • 4 years ago
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    thats true, we all arent hick lolol

  20. Alexis1994_13
    • 4 years ago
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    I was never think do mutliply with (2+5i). Thanks a lot guys! :D

  21. myininaya
    • 4 years ago
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    \[\frac{7+3i}{2+5i}*\frac{2-5i}{2-5i}=\frac{14-35i+6i-15i^2}{4-5i^2}\]

  22. myininaya
    • 4 years ago
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    lol

  23. myininaya
    • 4 years ago
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    go eat your breakfast

  24. joemath314159
    • 4 years ago
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    alright.....breakfast, i'll see you guys later lol

  25. Alexis1994_13
    • 4 years ago
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    I hope you will be here to answer and at my next questions :D lol

  26. myininaya
    • 4 years ago
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    are you in algebra?

  27. myininaya
    • 4 years ago
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    im confused because some of these questions seems algebra like and some look little different

  28. Alexis1994_13
    • 4 years ago
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    Yes,Algebra. Coplex part.

  29. myininaya
    • 4 years ago
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    complex part?

  30. Alexis1994_13
    • 4 years ago
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    At complex chapter.

  31. anonymous
    • 4 years ago
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    still up

  32. myininaya
    • 4 years ago
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    yep my hours are messed up

  33. anonymous
    • 4 years ago
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    wow you should get some sleep. not good to stare at computer all night

  34. myininaya
    • 4 years ago
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    i watched the racoons in backyard at 5 ish

  35. anonymous
    • 4 years ago
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    raccoons in the back yard?!

  36. myininaya
    • 4 years ago
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    i put cat food out for the wild cats but i seen like 5 racoons gang bang it this morning

  37. myininaya
    • 4 years ago
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    they are interesting

  38. Alexis1994_13
    • 4 years ago
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    Answer to my new question :D

  39. anonymous
    • 4 years ago
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    wild cats! raccoons! what in the world? any opossums?

  40. myininaya
    • 4 years ago
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    k

  41. anonymous
    • 4 years ago
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    i would think the cats would scare off the raccoons

  42. myininaya
    • 4 years ago
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    yes i see opossums around here

  43. anonymous
    • 4 years ago
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    i thought you were on the west coast. shows you what i know

  44. anonymous
    • 4 years ago
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    you doing complex variables problems?

  45. radar
    • 4 years ago
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    Alexis please review the multiplication of the denominator: (2+5i)(2-5i). It is not:\[4-5i ^{2}\]

  46. myininaya
    • 4 years ago
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    because its 4-25i^2 lol

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