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Alexis1994_13
 3 years ago
Best ResponseYou've already chosen the best response.0x/(x^2+y^2)yi/(x^2+y^2) is that right ?

darthsid
 3 years ago
Best ResponseYou've already chosen the best response.1\[\frac{1}{x+iy} = \frac{1}{x+iy} \times \frac{xiy}{xiy}\] now, multiplying the denominators and using the rule: \[ (m+n) times (mn) = m^2  n^2 \] we get: \[\frac{1}{x+iy} = \frac{xiy}{x^2(iy)^2}\] \[\frac{1}{x+iy} = \frac{xiy}{x^2i^2y^2}\] \[\frac{1}{x+iy} = \frac{xiy}{x^2(1)y^2}\] \[\frac{1}{x+iy} = \frac{xiy}{x^2+y^2}\] \[\frac{1}{x+iy} = \frac{x}{x^2+y^2} + i\frac{y}{x^2+y^2}\]
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