gfoste00
evaluate the expression and write the result in the form
a + bi.
(5 + 3i)(2 − i) over/3 + i



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abtrehearn
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10  5i + 6i 3i^2
= 10 + i + 3
= 13 + i.

abtrehearn
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:^)

lalaly
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(5+3i)(2i)= 105i+6i+3 = 13 + i
(13+i)/ (3+i)= 4i

gfoste00
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so wait which one is it?

lalaly
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4 i

abtrehearn
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I got the numerator. The whole problem is now reduced to
(13 + i)/(3 + i).

abtrehearn
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= (13 + i)(3  i)/[3 + i)(3 = i)]

abtrehearn
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= (39  13i + 3i  i^2)/10
(40  10i)/10
4  i.