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gfoste00

  • 4 years ago

evaluate the expression and write the result in the form a + bi. (5 + 3i)(2 − i) over/3 + i

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  1. abtrehearn
    • 4 years ago
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    10 - 5i + 6i -3i^2 = 10 + i + 3 = 13 + i.

  2. abtrehearn
    • 4 years ago
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    :^)

  3. lalaly
    • 4 years ago
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    (5+3i)(2-i)= 10-5i+6i+3 = 13 + i (13+i)/ (3+i)= 4-i

  4. gfoste00
    • 4 years ago
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    so wait which one is it?

  5. lalaly
    • 4 years ago
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    4- i

  6. abtrehearn
    • 4 years ago
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    I got the numerator. The whole problem is now reduced to (13 + i)/(3 + i).

  7. abtrehearn
    • 4 years ago
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    = (13 + i)(3 - i)/[3 + i)(3 = i)]

  8. abtrehearn
    • 4 years ago
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    = (39 - 13i + 3i - i^2)/10 (40 - 10i)/10 4 - i.

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