A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 5 years ago
really comfused with the acts. Check it out please.
(conjugate of z)*w=2+3x+(2x3)i
and (conjugate of w)*z=2+3x(2x3)i
Find x when you know this :[(conjugate of z)*w(conjugate of w)*z]/(2*i)=5*[(conjugate of z)*w+(conjugate of w)*z]/2
anonymous
 5 years ago
really comfused with the acts. Check it out please. (conjugate of z)*w=2+3x+(2x3)i and (conjugate of w)*z=2+3x(2x3)i Find x when you know this :[(conjugate of z)*w(conjugate of w)*z]/(2*i)=5*[(conjugate of z)*w+(conjugate of w)*z]/2

This Question is Closed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0now when you say (conjugate of z)*w you mean 2+3x+(2x3)i correct? so in the actual question you just replace the word with the equation am i getting that correct?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0okay give me a sec and ill work through it for you

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thanks,I am waiting,step by step please cause I lose it for some reason. :/

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Start with the right side \[5(2+3x+(2x3)i)+(2+3x(2x3)i)\]/2 \[10+15x+(10x15)i+10+15x(10x15)i\] \[(20+30x)/2\] left side \[2+3x+(2x3)i(2+3x(2x3)i)\] \[[(2x3)i+(2x3)i]/[2i]\] in total we then have \[[(2x3)i+(2x3)i]/[2i] = (20+30x)/2\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0now are you trying to solve for x? or just simplyfy

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I found it,thanks a lot.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.