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Alexis1994_13 Group Title

really comfused with the acts. Check it out please. (conjugate of z)*w=2+3x+(2x-3)i and (conjugate of w)*z=2+3x-(2x-3)i Find x when you know this :[(conjugate of z)*w-(conjugate of w)*z]/(2*i)=5*[(conjugate of z)*w+(conjugate of w)*z]/2

  • 3 years ago
  • 3 years ago

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  1. Mercury21 Group Title
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    now when you say (conjugate of z)*w you mean 2+3x+(2x-3)i correct? so in the actual question you just replace the word with the equation am i getting that correct?

    • 3 years ago
  2. Alexis1994_13 Group Title
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    yes

    • 3 years ago
  3. Mercury21 Group Title
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    okay give me a sec and ill work through it for you

    • 3 years ago
  4. Alexis1994_13 Group Title
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    thanks,I am waiting,step by step please cause I lose it for some reason. :/

    • 3 years ago
  5. Mercury21 Group Title
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    Start with the right side \[5(2+3x+(2x-3)i)+(2+3x-(2x-3)i)\]/2 \[10+15x+(10x-15)i+10+15x-(10x-15)i\] \[(20+30x)/2\] left side \[2+3x+(2x-3)i-(2+3x-(2x-3)i)\] \[[(2x-3)i+(2x-3)i]/[2i]\] in total we then have \[[(2x-3)i+(2x-3)i]/[2i] = (20+30x)/2\]

    • 3 years ago
  6. Mercury21 Group Title
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    now are you trying to solve for x? or just simplyfy

    • 3 years ago
  7. Alexis1994_13 Group Title
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    I found it,thanks a lot.

    • 3 years ago
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