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Alexis1994_13
 4 years ago
really comfused with the acts. Check it out please.
(conjugate of z)*w=2+3x+(2x3)i
and (conjugate of w)*z=2+3x(2x3)i
Find x when you know this :[(conjugate of z)*w(conjugate of w)*z]/(2*i)=5*[(conjugate of z)*w+(conjugate of w)*z]/2
Alexis1994_13
 4 years ago
really comfused with the acts. Check it out please. (conjugate of z)*w=2+3x+(2x3)i and (conjugate of w)*z=2+3x(2x3)i Find x when you know this :[(conjugate of z)*w(conjugate of w)*z]/(2*i)=5*[(conjugate of z)*w+(conjugate of w)*z]/2

This Question is Closed

Mercury21
 4 years ago
Best ResponseYou've already chosen the best response.1now when you say (conjugate of z)*w you mean 2+3x+(2x3)i correct? so in the actual question you just replace the word with the equation am i getting that correct?

Mercury21
 4 years ago
Best ResponseYou've already chosen the best response.1okay give me a sec and ill work through it for you

Alexis1994_13
 4 years ago
Best ResponseYou've already chosen the best response.0thanks,I am waiting,step by step please cause I lose it for some reason. :/

Mercury21
 4 years ago
Best ResponseYou've already chosen the best response.1Start with the right side \[5(2+3x+(2x3)i)+(2+3x(2x3)i)\]/2 \[10+15x+(10x15)i+10+15x(10x15)i\] \[(20+30x)/2\] left side \[2+3x+(2x3)i(2+3x(2x3)i)\] \[[(2x3)i+(2x3)i]/[2i]\] in total we then have \[[(2x3)i+(2x3)i]/[2i] = (20+30x)/2\]

Mercury21
 4 years ago
Best ResponseYou've already chosen the best response.1now are you trying to solve for x? or just simplyfy

Alexis1994_13
 4 years ago
Best ResponseYou've already chosen the best response.0I found it,thanks a lot.
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