determine bases for the following subspaces of R^3 a) the plane 3x-2y+5z

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determine bases for the following subspaces of R^3 a) the plane 3x-2y+5z

Mathematics
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sir its my pleasure that you are helping me
That plane 3x - 2y + 5x = 0 is a two dimensional subapace of \[\mathbb{R}^{3} .\] If we solve for z in terms of x and y, we get z = (-3x + 2y)/5. Letting x = 1, y = 0 makes z = -3/5. Letting x = 0, y = 1 makes z = 2/5, so two linearly independent vectors in the subspace are [1,0,-3/5] and [0,1, 2/5]. Those two vectors form a basis for the subspace \[B = \left\{ [x, y, z]|3x - 2y + 5z = 0 \right\}.\]

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Consider the operation on p2 that takes ax^2+bx+c to cx^2+bx+a . Does it correspond to a linear transformation from R^3 to R^3 ? If so, what is its matrix? (b) Consider the operation on p3 that takesax^3+bx^2+cx+d to cx^3-bx^2-ax+d . Does it correspond to a linear transformation from R^3 to R^3 ? If so, what is its matrix?
can you solve above question
Someone help on my problems.
Let us consider n, a unit normal vector to the plane at the origin, and \[u_1 ,\] the unit vector in the direction of [1, 0 ,-3/5]. \[n = [3, -2, 5]/\sqrt{3^{2} + (-2)^{2} + 5^{2},}\] \[u_1 = [5/\sqrt{34}, 0 -3/\sqrt{34}].\] If we take the cross product of unit normal vector N with \[u_1 ,\]we get another unit vector \[u_2\]in the subspace S, so those two vectors form another basis if S; in fact, it is an orthonormal basis of S. To determine what \[u_2\]is, evaluate the determinant of matrix [[ i, j, k ], [3/sqrt(38), -2/sqrt(38), 5/sqrt(38)], [5/sqrt(34), 0, -3/sqrt(34)]] = [6/sqrt(1292), 34/sqrt(1292), 10/sqrt(1292)], simplifying to [3/ sqrt(323), 17/sqrt(323), 5/sqrt(323) ]. Thus, an orthonormal basis for subspace S is\[\left\{ u_1, u_2 \right\},\]where \[u_1 = [5/\sqrt{34}, 0, -3/\sqrt{34}],\] \[u_2 = [3/\sqrt{323}, 17/\sqrt{323}, 5/\sqrt{323}].\]
solve this please (b) Consider the operation on p3 that takes ax^3+bx^2+cx+d to cx^3-bx^2-ax+d . Does it correspond to a linear transformation from R^3 to R^3 ? If so, what is its matrix?
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sir can you solve the question i posted recently
Let me see can I find it...

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