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lar0213
y-1=(x-2)^2. use the vertex and intercepts to sketch a graph of the quadratic function
The vertex of the parabola is at (2, 1), reading off the given equation. The y-intercept is determined by plugging 1 for x and folve for y, so yhe y-intercept is at (5,0). To get the x-intercepts, plug 0 in for y and solve for x. You then get a square equalling a negative number, so there are no x-intercepts.
The y-intercept is at (0,5), not (5,0).