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Nickie_S
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Can you help me, not sure where this one wants me to go, can you help me step by step? Andrew factored the expression 4x^3 +2x^2 +8x as 2x(4x^22x8). But when Melissa applied the distributive law and multiplied out 2x(4x^22x8), she got 8x^3+4x^2 +16x; thus, Andrew's solution does not appear to check. Why is that? Please help Andrew to understand this better. Explain your reasoning and correctly factor the original expression, if possible. If the expression is prime, so state. Walk me through it, thank you!
 3 years ago
 3 years ago
Nickie_S Group Title
Can you help me, not sure where this one wants me to go, can you help me step by step? Andrew factored the expression 4x^3 +2x^2 +8x as 2x(4x^22x8). But when Melissa applied the distributive law and multiplied out 2x(4x^22x8), she got 8x^3+4x^2 +16x; thus, Andrew's solution does not appear to check. Why is that? Please help Andrew to understand this better. Explain your reasoning and correctly factor the original expression, if possible. If the expression is prime, so state. Walk me through it, thank you!
 3 years ago
 3 years ago

This Question is Closed

abtrehearn Group TitleBest ResponseYou've already chosen the best response.1
Andrew was correct in factoring out the 2x. Where he introduced an error was in the quadratic factor. He forgor th cut the coefficients in half. The correct factorization is\[2x(2x^{2}  x  4)\].
 3 years ago

Nickie_S Group TitleBest ResponseYou've already chosen the best response.0
Thanks for your help. I will have one more question to do today, then I am done. I am going to try to do it by myself, but if I need help I will come back here for it.
 3 years ago

abtrehearn Group TitleBest ResponseYou've already chosen the best response.1
Okay. I'll keep an eye open for you.
 3 years ago
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