vishweshshrimali5
  • vishweshshrimali5
A fair die is rolled four times. The probability that each of the final three rolls is at least as large as the roll preceeding it is m/n in the lowest terms. Then n -10m = ?
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
Please stop spamming and wait patiently for a tutor to assist you with your problems.
vishweshshrimali5
  • vishweshshrimali5
KKKKKKK sorry
vishweshshrimali5
  • vishweshshrimali5
Hey!! Xcuseme Who are you polpak ? May I know please?

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anonymous
  • anonymous
Just a lego guy
vishweshshrimali5
  • vishweshshrimali5
What is lego guy ?
vishweshshrimali5
  • vishweshshrimali5
I mean what does it mean ?
vishweshshrimali5
  • vishweshshrimali5
Hey You have 580 medals !!!!!!!!!! wow
anonymous
  • anonymous
this question is a poser
anonymous
  • anonymous
Others have more.
vishweshshrimali5
  • vishweshshrimali5
Hello satellite please help me !
vishweshshrimali5
  • vishweshshrimali5
What is a poser !
anonymous
  • anonymous
are u studying iit coaching
vishweshshrimali5
  • vishweshshrimali5
No but preparing for that but how do u know that man ?
anonymous
  • anonymous
if the first roll is a1, then probability is 1 if the first roll is a 2 then probability is \[(\frac{5}{6})^3\]
anonymous
  • anonymous
that type of question comes in iit
vishweshshrimali5
  • vishweshshrimali5
Yaa u are right amingad !
anonymous
  • anonymous
it is easy take 4 turn as 36c4
vishweshshrimali5
  • vishweshshrimali5
How do u got that satellite please explain !
anonymous
  • anonymous
oh wait that is wrong. i need to read more carefully
vishweshshrimali5
  • vishweshshrimali5
Please take you time
vishweshshrimali5
  • vishweshshrimali5
How do you got that amingad
anonymous
  • anonymous
looks like coupon collectors problem
vishweshshrimali5
  • vishweshshrimali5
It may be
anonymous
  • anonymous
what is probability of a record. gives harmonic series
anonymous
  • anonymous
yikes now i have to think
vishweshshrimali5
  • vishweshshrimali5
Amingad please explain step by step I can't understand it so fastly
vishweshshrimali5
  • vishweshshrimali5
I am a neophyte in this field you may think that
anonymous
  • anonymous
fair dice consist of 6 numbers . so the the no of times get the highest probability of number will be 24 c4 my mistake i wrote 36 c4
anonymous
  • anonymous
you lost me here for sure
vishweshshrimali5
  • vishweshshrimali5
What do you mean to say satellite ?
vishweshshrimali5
  • vishweshshrimali5
Okkkkk amingad now is there any step left ?
anonymous
  • anonymous
i mean i am lost completely.
vishweshshrimali5
  • vishweshshrimali5
Ohhhh you mean that it is a nice question then thanks a lot
vishweshshrimali5
  • vishweshshrimali5
Well satellite you can have a look at other questions
anonymous
  • anonymous
12c3< m/ n so n has to be highest dice to be rolled
vishweshshrimali5
  • vishweshshrimali5
Amingad will you please do me a favour
anonymous
  • anonymous
yep it is tricky but good
vishweshshrimali5
  • vishweshshrimali5
can you write the answer in a single post and with each step explained Because my teacher says that you will have to answer the question with each step explained or you will get no marks
vishweshshrimali5
  • vishweshshrimali5
Will you please do so ?
vishweshshrimali5
  • vishweshshrimali5
Are you answering the question amingad
Zarkon
  • Zarkon
\[\frac{7}{72}\]
anonymous
  • anonymous
yep correct answer zarkon
Zarkon
  • Zarkon
i know
Zarkon
  • Zarkon
Just for fun...if we used an n-sided die the probability is \[\frac{(n+1)(n+2)(n+3)}{24n^3}\]
Zarkon
  • Zarkon
and if we rolled an n-sided die k times it would be \[\frac{n(n+1)(n+2)\cdots(n+k-1)}{n^{k}k!}\]

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