A fair die is rolled four times. The probability that each of the final three rolls is at least as large as the roll preceeding it is m/n in the lowest terms. Then n -10m = ?

- vishweshshrimali5

- schrodinger

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- anonymous

Please stop spamming and wait patiently for a tutor to assist you with your problems.

- vishweshshrimali5

KKKKKKK sorry

- vishweshshrimali5

Hey!! Xcuseme Who are you polpak ? May I know please?

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## More answers

- anonymous

Just a lego guy

- vishweshshrimali5

What is lego guy ?

- vishweshshrimali5

I mean what does it mean ?

- vishweshshrimali5

Hey You have 580 medals !!!!!!!!!! wow

- anonymous

this question is a poser

- anonymous

Others have more.

- vishweshshrimali5

Hello satellite please help me !

- vishweshshrimali5

What is a poser !

- anonymous

are u studying iit coaching

- vishweshshrimali5

No but preparing for that but how do u know that man ?

- anonymous

if the first roll is a1, then probability is 1
if the first roll is a 2 then probability is
\[(\frac{5}{6})^3\]

- anonymous

that type of question comes in iit

- vishweshshrimali5

Yaa u are right amingad !

- anonymous

it is easy take 4 turn as 36c4

- vishweshshrimali5

How do u got that satellite please explain !

- anonymous

oh wait that is wrong. i need to read more carefully

- vishweshshrimali5

Please take you time

- vishweshshrimali5

How do you got that amingad

- anonymous

looks like coupon collectors problem

- vishweshshrimali5

It may be

- anonymous

what is probability of a record. gives harmonic series

- anonymous

yikes now i have to think

- vishweshshrimali5

Amingad please explain step by step I can't understand it so fastly

- vishweshshrimali5

I am a neophyte in this field you may think that

- anonymous

fair dice consist of 6 numbers . so the the no of times get the highest probability of number will be 24 c4 my mistake i wrote 36 c4

- anonymous

you lost me here for sure

- vishweshshrimali5

What do you mean to say satellite ?

- vishweshshrimali5

Okkkkk amingad now is there any step left ?

- anonymous

i mean i am lost completely.

- vishweshshrimali5

Ohhhh you mean that it is a nice question then thanks a lot

- vishweshshrimali5

Well satellite you can have a look at other questions

- anonymous

12c3< m/ n so n has to be highest dice to be rolled

- vishweshshrimali5

Amingad will you please do me a favour

- anonymous

yep it is tricky but good

- vishweshshrimali5

can you write the answer in a single post and with each step explained
Because my teacher says that you will have to answer the question with each step explained or you will get no marks

- vishweshshrimali5

Will you please do so ?

- vishweshshrimali5

Are you answering the question amingad

- Zarkon

\[\frac{7}{72}\]

- anonymous

yep correct answer zarkon

- Zarkon

i know

- Zarkon

Just for fun...if we used an n-sided die the probability is
\[\frac{(n+1)(n+2)(n+3)}{24n^3}\]

- Zarkon

and if we rolled an n-sided die k times it would be
\[\frac{n(n+1)(n+2)\cdots(n+k-1)}{n^{k}k!}\]

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