anonymous
  • anonymous
Find f(-2) if f(x) = 2x2 + kx + 2 and f(1) = 3.
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
need help
anonymous
  • anonymous
replace x by 1 and solve \[f(1)=2+k+2=3\] for k
anonymous
  • anonymous
k=-1?

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anonymous
  • anonymous
no it is wrong
anonymous
  • anonymous
We find what k is by plugging 1nfor x into the original function and setting the result equal to 3: 2*1^2 + k*1 + 2 = 3, so k = -1, and the function is\[f(x) = 2x^{2} - x + 2.\]We evaluate this function at x = -2: f(-2) = 8.
anonymous
  • anonymous
so what is its' result?
anonymous
  • anonymous
I glitched. f(-2) = 12.
anonymous
  • anonymous
why?
anonymous
  • anonymous
Did you get k = -1?
anonymous
  • anonymous
yes
anonymous
  • anonymous
looks like if you solve larger less than twice the smaller. make x the larger then we get \[2+k+2=3\] you get \[k=-1\] yes? so now you have \[f(x)=2x^2-x+2\] and if you want \[f(-2)\] you compute \[f(-2)=2(-2)^2-(-2)+2\]
anonymous
  • anonymous
oh ok
anonymous
  • anonymous
You use the information to find the value of f(-2).
anonymous
  • anonymous
ok I understand now.Thanks
anonymous
  • anonymous
:^)

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