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satellite73
 3 years ago
Best ResponseYou've already chosen the best response.0replace x by 1 and solve \[f(1)=2+k+2=3\] for k

abtrehearn
 3 years ago
Best ResponseYou've already chosen the best response.0We find what k is by plugging 1nfor x into the original function and setting the result equal to 3: 2*1^2 + k*1 + 2 = 3, so k = 1, and the function is\[f(x) = 2x^{2}  x + 2.\]We evaluate this function at x = 2: f(2) = 8.

dang_thitham
 3 years ago
Best ResponseYou've already chosen the best response.1so what is its' result?

abtrehearn
 3 years ago
Best ResponseYou've already chosen the best response.0I glitched. f(2) = 12.

satellite73
 3 years ago
Best ResponseYou've already chosen the best response.0looks like if you solve larger less than twice the smaller. make x the larger then we get \[2+k+2=3\] you get \[k=1\] yes? so now you have \[f(x)=2x^2x+2\] and if you want \[f(2)\] you compute \[f(2)=2(2)^2(2)+2\]

abtrehearn
 3 years ago
Best ResponseYou've already chosen the best response.0You use the information to find the value of f(2).

dang_thitham
 3 years ago
Best ResponseYou've already chosen the best response.1ok I understand now.Thanks
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