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5369855
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For the function: 2x^4 3x^3 + 2x4, find the zeroes. Show all work
 3 years ago
 3 years ago
5369855 Group Title
For the function: 2x^4 3x^3 + 2x4, find the zeroes. Show all work
 3 years ago
 3 years ago

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LordBhael Group TitleBest ResponseYou've already chosen the best response.1
Alright, good sir! Allow me to help! We need to factor this sucker, so hold on to your knickers. We have an x^4 an x^3 and an x^1 (or just x), so we need to factor using x^3 and x since we can make the x^4 through multiplication. We have the following equation: 2x^4  3x^3 + 2x 4 = 0 We set the equation equal to zero so we can find when it crosses the x axis (the zeroes). Now, we want to use our own numeral for the final number so let's move it over to the other side: 2x^4  3x^3 + 2x = 4 Lets try factoring this. Through some serious trial and error (not that hard, just see what you have to multiply to find this number) you can find the factors: (x^3 + __ )*(2x + __ ) = 4 + __ I got the 2 in front of the x because I knew we needed a 2x^4. Now, try it out and find what you need  here a 1 and 3 work: (x^3 + 1 )*(2x  3 ) = 4 + __ Now we need to find that number on the other side of the equation, so multiply the two out: 2x^4  3x^3 +2x  3 = 4  3 It ended up being 3. Fun Fun. Now lets go back to the factors and put that 3 in: (x^3 +1)*(2x  3) = 1 Now, we need to make this equation work and the only way this will work is if both parts on the left equal 1: (x^3 +1) = 1 and (2x3)=1 x^3=0 and 2x=4 x=0 and x=2 There you go! I really hope I didn't make a mistake anywhere o.o.
 3 years ago

5369855 Group TitleBest ResponseYou've already chosen the best response.0
Wow thank you so much! I know that took a lot of time. I would give you 100 medals if I could!
 3 years ago
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