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panther77
 4 years ago
If you are looking at a graph of a quadratic equation, how do you determine where the solutions are?
panther77
 4 years ago
If you are looking at a graph of a quadratic equation, how do you determine where the solutions are?

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5369855
 4 years ago
Best ResponseYou've already chosen the best response.0Do you mean the zeroes?

panther77
 4 years ago
Best ResponseYou've already chosen the best response.0i am just starting on quadratic equations i think its asking me what i would look for to determine a solution

jim_thompson5910
 4 years ago
Best ResponseYou've already chosen the best response.1The solutions are synonymous with the zeros or the roots. The xintercepts are the points where the graph crosses the x axis. The x coordinates of these points will represent the solutions or zeros of the quadratic equation.

panther77
 4 years ago
Best ResponseYou've already chosen the best response.0this stuff is enough to melt the brain

5369855
 4 years ago
Best ResponseYou've already chosen the best response.0Ok, so this is referring to finding the zeroes. To do this, you simply split the quadratic equation into two separate equations and and solve for x

5369855
 4 years ago
Best ResponseYou've already chosen the best response.0Ex: if the equation was: x^26x+9, you would split it into: (x3)(x3). This means the zero is at 3. It also means that at 3, there is a multiplicity since x=3 happens twice

panther77
 4 years ago
Best ResponseYou've already chosen the best response.0oh boy cant wait to do this more

panther77
 4 years ago
Best ResponseYou've already chosen the best response.0ty for your help i think im gonna need to post some problems and see how to work them

panther77
 4 years ago
Best ResponseYou've already chosen the best response.0did you see the other post i had i can post it here if you know it

panther77
 4 years ago
Best ResponseYou've already chosen the best response.0http://openstudy.com/groups/mathematics/updates/4e26540a0b8b3d38d3b80246

5369855
 4 years ago
Best ResponseYou've already chosen the best response.0i'm sorry I'm not too sure.
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