Here's the question you clicked on:
adnanchowdhury
I don't understand what PS1b is asking for? I have completed PS1a - find the 1000th prime number and gained the correct answer.
ps1b is asking you to first compute logarithms of the prime numbers you just printed , then print sum all the logarithms and then print the ratio of sum of logarithm and the last prime number you just got. it doesn't want you to print ratio of sum and number of prime numbers instead the ratio of sum and last prime number.
yes, jaskaran is right. you take the logarithms of all of the 1000 primes you've calculated, starting with the number two (2) and going all the way to some arbitrary prime number N that is less than your 1000th prime number. you add all of these values (the logarithms of the primes from 2 to N) and compute the ratio of this sum to N. you then repeat this process, making your next-highest prime number the new N, and repeat it again and again until you have reached your 1000th prime. so your first computation will be (log(2) + log(3))/(3), and your second computation will be (log(2) + log(3) + log(5))/(5). so the format is (log(2) + log(3) + ... + log(N))/(N).