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solved it, go to you original post

so here you have 4 equations

\[y+1=-(x-4)^2\] \[y= -x^2+3x-4\] \[y=(x+1)(x-3)\] \[y=-(x+1)(x-3)\]

yeah hold on

you want an x intercept of 3, therefore then y=0, the function will x will be 3

Also we know this a downward facing parabola because of the negative sign

so how do you tell which equation will make what type of parabola?

thanks guys!

we want this function to me moved to the right 3 units