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kassia
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Which one of these equations would make a graph with a downward facing parabola with an x intercept of 3 and a y intercept of 3 y+1=(x4)^2; y= x^2+3x4; y=(x+1)(x3); y=(x+1)(x3)
 3 years ago
 3 years ago
kassia Group Title
Which one of these equations would make a graph with a downward facing parabola with an x intercept of 3 and a y intercept of 3 y+1=(x4)^2; y= x^2+3x4; y=(x+1)(x3); y=(x+1)(x3)
 3 years ago
 3 years ago

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AntiMatter Group TitleBest ResponseYou've already chosen the best response.1
All right, when you graph the function \[y=x^{2}\] you get a parabola, centered at the origin, it faces up
 3 years ago

LagrangeSon678 Group TitleBest ResponseYou've already chosen the best response.0
solved it, go to you original post
 3 years ago

AntiMatter Group TitleBest ResponseYou've already chosen the best response.1
so here you have 4 equations
 3 years ago

AntiMatter Group TitleBest ResponseYou've already chosen the best response.1
\[y+1=(x4)^2\] \[y= x^2+3x4\] \[y=(x+1)(x3)\] \[y=(x+1)(x3)\]
 3 years ago

kassia Group TitleBest ResponseYou've already chosen the best response.0
i saw that you solved it for a second and then the computer im on decided to be uncoperative so i can no longer view it is it possible for you to copy and paste sorry for the hassle
 3 years ago

LagrangeSon678 Group TitleBest ResponseYou've already chosen the best response.0
yeah hold on
 3 years ago

LagrangeSon678 Group TitleBest ResponseYou've already chosen the best response.0
The answer to your question is : y=(x+1)(x3). Why? becuase from the factored form we see that there will be an xintercept at (3,0). TO get the y intercept you have to replace x with zero and evluate. you will get (0,3).
 3 years ago

AntiMatter Group TitleBest ResponseYou've already chosen the best response.1
you want an x intercept of 3, therefore then y=0, the function will x will be 3
 3 years ago

LagrangeSon678 Group TitleBest ResponseYou've already chosen the best response.0
Also we know this a downward facing parabola because of the negative sign
 3 years ago

kassia Group TitleBest ResponseYou've already chosen the best response.0
so how do you tell which equation will make what type of parabola?
 3 years ago

LagrangeSon678 Group TitleBest ResponseYou've already chosen the best response.0
Will a downward facing parabola should have a negative sign on the leading term. It is best to expand y=(x+1)(x3), You should get y=x^22x3
 3 years ago

LagrangeSon678 Group TitleBest ResponseYou've already chosen the best response.0
now that you have this expaned, you can see that this indeed will be a parabola because of the x^2 term. Then you also have the factored form. To get the x and y intecepts, in this case, it is good to use the factored from. To get yint set x to be zero and solve. To get xintercpet set y to be zero and solve.
 3 years ago

AntiMatter Group TitleBest ResponseYou've already chosen the best response.1
so starting with \[y=x^2\] we can transform this into the equation we want. so y intercept of 3, that means when x = 0 the function will equal 3, therefore, consider the basic parabola, \[3=(0^2)\], so you need to add 3 therefore it becomes \[y=x^2 + 3\]
 3 years ago

kassia Group TitleBest ResponseYou've already chosen the best response.0
thanks guys!
 3 years ago

AntiMatter Group TitleBest ResponseYou've already chosen the best response.1
now consider the x intercept of 3, that means when y=0, the function will equal 3.... we now have \[y=x^2+3\]
 3 years ago

AntiMatter Group TitleBest ResponseYou've already chosen the best response.1
we want this function to me moved to the right 3 units
 3 years ago

AntiMatter Group TitleBest ResponseYou've already chosen the best response.1
sorry, this isn't the right approach, let's just analyze the given functions, however, it seems your question was already answered
 3 years ago
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