Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

Which one of these equations would make a graph with a downward facing parabola with an x intercept of 3 and a y intercept of 3 y+1=-(x-4)^2; y= -x^2+3x-4; y=(x+1)(x-3); y=-(x+1)(x-3)

See more answers at
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer


To see the expert answer you'll need to create a free account at Brainly

All right, when you graph the function \[y=x^{2}\] you get a parabola, centered at the origin, it faces up
solved it, go to you original post
so here you have 4 equations

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

\[y+1=-(x-4)^2\] \[y= -x^2+3x-4\] \[y=(x+1)(x-3)\] \[y=-(x+1)(x-3)\]
i saw that you solved it for a second and then the computer im on decided to be uncoperative so i can no longer view it is it possible for you to copy and paste sorry for the hassle
yeah hold on
The answer to your question is : y=-(x+1)(x-3). Why? becuase from the factored form we see that there will be an xintercept at (3,0). TO get the y intercept you have to replace x with zero and evluate. you will get (0,3).
you want an x intercept of 3, therefore then y=0, the function will x will be 3
Also we know this a downward facing parabola because of the negative sign
so how do you tell which equation will make what type of parabola?
Will a downward facing parabola should have a negative sign on the leading term. It is best to expand y=-(x+1)(x-3), You should get y=-x^2-2x-3
now that you have this expaned, you can see that this indeed will be a parabola because of the x^2 term. Then you also have the factored form. To get the x and y intecepts, in this case, it is good to use the factored from. To get y-int set x to be zero and solve. To get x-intercpet set y to be zero and solve.
so starting with \[y=x^2\] we can transform this into the equation we want. so y intercept of 3, that means when x = 0 the function will equal 3, therefore, consider the basic parabola, \[3=(0^2)\], so you need to add 3 therefore it becomes \[y=x^2 + 3\]
thanks guys!
now consider the x intercept of 3, that means when y=0, the function will equal 3.... we now have \[y=x^2+3\]
we want this function to me moved to the right 3 units
sorry, this isn't the right approach, let's just analyze the given functions, however, it seems your question was already answered

Not the answer you are looking for?

Search for more explanations.

Ask your own question