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okay use this formula: a^2-b^2=(a-b)(a+b)
ur a=2x, b=3y
difference of 2 squares
This is a difference of squares: A^2-B^2=(A+B)(A-B) In this case, A=2x and B=3y So 4x^2-9y^2=(2x+3y)(2x-3y)
Plug that in and get the answer, this is simple, you can doit yourself
and jim, guide them but don't post the answers, i think they should do it themselves.
What I mean is tell them what to do.
i really wish i understood all of this lol
true, but I find it helps to step them through it
sarsar56, you will need this in your future life.
it weill be (2x+3y)(2x-3y)
if not sarsar, let me know
9x^2+16 so how would id o this one
Well jim we already factored a couple of problems. Like see what i mean, tell them to use this formula: a^2-b^2 = (a-b)(a+b) Tell them to observe that: 4x2 - 9y2 = (2x)^2-(3y)^2, and tell them to do the substitution to factor.
Sarsar I don't think that's factorable.
Wait we can complete the square
you can complete the square, but that won't make it factorable
how do u know if something is not factorablw
thi will be like this (3x+4)(3x-4)
I think it can be factored
if you have a sum of squares, then it is NOT factorable.
whats a sum of squares
9x^2+16 (3x)^2 + 2*3x*4 + 4^2 - 2*3x*4
a square is any expression that can be represented by squaring another expression. For example, 4 is a square of 2 since 2 squared = 4 Also, 4x^2 = (2x)^2 is another square
ouch i am sorry i thought there is minuse so sorry!!!
And then: (3x+4-sqrt(24x))(3x+4+sqrt(24x))
I mean that just makes it uglier haha
but when they say "factorable", they mean over the rationals.
and you forgot the imaginary terms, which makes it even worse
oh i guess, i mean i never learned how u guys do it here in the US.
i kind of see it but not really ):
don't worry about it, 9x^2+16 is NOT factorable
how about this one 2xy-xz+2wy-wz
Okay sarsar observe what is similar in the equation
which would b the 2y?
2xy-xz+2wy-wz 2xy+2wy-xz-wz 2y(x+w)-z(x+w)
i think u can do like this : 9x^2 +9+7 then we wil factor : 9(x^2+1)+7 then:( 9+7)(x^2+1)
am i right?
4ax + 8ay + 3bx + 6by so like in this one, do i start by taking out the GCF?
sorry Roh, that's not the correct factorization. You can verify that by expanding
no u pulled out 9+7, u can't do that
first, group terms (4ax + 8ay) + (3bx + 6by)
what comes next?
mmmm yeah ur right bahroom
Jim where did u get that one from?
oh u just took it as an example? I see was talkin about this (4ax + 8ay) + (3bx + 6by)
ahhhhh im confused lol
I think ima leave, having too much people to help confuses others
yoou can factor it by group factoring sarsar no confusing is needed let me do it
4ax + 8ay + 3bx + 6by (4ax + 8ay) + (3bx + 6by) 4a(x + 2y) + 3b(x + 2y) (4a+3b)(x + 2y)
4ax + 8ay + 3bx + 6by ok so u group the terms (4ax+8ay) (3bx+6by)
first group the terms, then pull out the GCF from each group. From there, combine like terms.