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okay use this formula:
a^2-b^2=(a-b)(a+b)

ur a=2x, b=3y

difference of 2 squares

Plug that in and get the answer, this is simple, you can doit yourself

and jim, guide them but don't post the answers, i think they should do it themselves.

What I mean is tell them what to do.

i really wish i understood all of this lol

true, but I find it helps to step them through it

sarsar56, you will need this in your future life.

it weill be (2x+3y)(2x-3y)

if not sarsar, let me know

9x^2+16 so how would id o this one

Sarsar I don't think that's factorable.

Wait we can complete the square

you can complete the square, but that won't make it factorable

how do u know if something is not factorablw

thi will be like this (3x+4)(3x-4)

I think it can be factored

if you have a sum of squares, then it is NOT factorable.

whats a sum of squares

9x^2+16
(3x)^2 + 2*3x*4 + 4^2 - 2*3x*4

(3x+4)^2-24x

ouch i am sorry i thought there is minuse so sorry!!!

And then:
(3x+4-sqrt(24x))(3x+4+sqrt(24x))

I mean that just makes it uglier haha

but when they say "factorable", they mean over the rationals.

and you forgot the imaginary terms, which makes it even worse

oh i guess, i mean i never learned how u guys do it here in the US.

i kind of see it but not really ):

don't worry about it, 9x^2+16 is NOT factorable

how about this one 2xy-xz+2wy-wz

Okay sarsar observe what is similar in the equation

which would b the 2y?

2xy-xz+2wy-wz
2xy+2wy-xz-wz
2y(x+w)-z(x+w)

So:
(x+w)(2y-z)

i think u can do like this : 9x^2 +9+7
then we wil factor : 9(x^2+1)+7
then:( 9+7)(x^2+1)

am i right?

4ax + 8ay + 3bx + 6by
so like in this one, do i start by taking out the GCF?

sorry Roh, that's not the correct factorization. You can verify that by expanding

no u pulled out 9+7, u can't do that

first, group terms
(4ax + 8ay) + (3bx + 6by)

what comes next?

mmmm yeah ur right bahroom

Jim where did u get that one from?

which one?

oh u just took it as an example? I see
was talkin about this (4ax + 8ay) + (3bx + 6by)

ahhhhh im confused lol

I think ima leave, having too much people to help confuses others

*too many

yoou can factor it by group factoring sarsar no confusing is needed let me do it

4ax + 8ay + 3bx + 6by
(4ax + 8ay) + (3bx + 6by)
4a(x + 2y) + 3b(x + 2y)
(4a+3b)(x + 2y)

4ax + 8ay + 3bx + 6by
ok so u group the terms
(4ax+8ay) (3bx+6by)

first group the terms, then pull out the GCF from each group. From there, combine like terms.

4a(x+2y)+3b(x+2y)
(x+2y)(4a+3b)