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(x8)^2=36 find exact and approximate solutions to three decimal places.
a) solve 8x+x(x6)=0
b) find the xintercepts of f(x)=8x+x(x6) a)what are the solution x=?
c) what are the xintercepts
 2 years ago
 2 years ago
(x8)^2=36 find exact and approximate solutions to three decimal places. a) solve 8x+x(x6)=0 b) find the xintercepts of f(x)=8x+x(x6) a)what are the solution x=? c) what are the xintercepts
 2 years ago
 2 years ago

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imranmeah91Best ResponseYou've already chosen the best response.0
8x+x(x6) or (x8)^2=36 ?
 2 years ago

aama100Best ResponseYou've already chosen the best response.0
a) (x8)^2=36 find exact and approximate solutions to three decimal places. b) solve 8x+x(x6)=0 c) find the xintercepts of f(x)=8x+x(x6) 1)what are the solution x=?
 2 years ago

myininayaBest ResponseYou've already chosen the best response.0
a) take square root of both sides: x8=pm 6 pm means plus or minus then add 8 on both sides
 2 years ago

saljudieh07Best ResponseYou've already chosen the best response.0
x^216X+64=36 X^216X+28=0 Then, just find it using the quadratic formula, so the answers will be: (16+/12)/2= 14 or 2 Myiniaya i think that way is incorrect because you are cancelling one of the roots, and you need all the answers
 2 years ago

polpakBest ResponseYou've already chosen the best response.1
She said \(\pm 6\) which is not cancelling one of the roots.
 2 years ago

polpakBest ResponseYou've already chosen the best response.1
\[(x8)^2 = 36\]\[\implies x8 = \pm6\]\[\implies x = 8\pm 6\]\[\implies x \in \{2,14\}\]
 2 years ago

saljudieh07Best ResponseYou've already chosen the best response.0
for b) you have (8x+x)(x6)=0 expand: 8x^248x+x^26x=0 simplify: 9x^254x=0 x=0 OR x= 5 and polpak, sorry didnt pay attention to the pm, so pm is +/, and yes that would be correct!
 2 years ago
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