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what expression?

... so, at time = 3, the velocity is 96? ....so f(3) = 96? inverse would be... f'(96) = 3?

Is that how it works? It's that simple???

or is it t=f^-1(v)?

or would it be 3^-1(96)?

Oh, the equation might b3e v=f(t)=32t
so the inverse of that would be t=f^-1(v)

no.
v = 32t (swap v and t)
t = 32v (solve for v)
t/32 = v
therefore,
\[f ^{-1}(t) = t/32\]

ok thanks!