okayimhere
In Triangle ABC, Cos B = (9/12) find Sin B.
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okayimhere
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estudier
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SOHCAHTOA/Pythagorus
estudier
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U know SOHCAHTOA?
mathematicalpro
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cos = Adjacent/Hypotenuse
for finding the third side use pythagorus theorem
so,AC^2 =AB^2-BC^2
= 12^2-9^2
= 144-81
=63
AC = root 63
AC = 7.9
sinB = Opposite/hypotenuse
= 7.9/12
okayimhere
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I'm still pretty unfamiliar with SOHCAHTOA.. I am trying to learn it though...
nikhilchabe
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since cosB=9/12.sinB(opp side/hyp=root 63/12..
okayimhere
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Oh, okay, thankyou guys,[;