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okayimhere
 3 years ago
In Triangle ABC, Cos B = (9/12) find Sin B.
okayimhere
 3 years ago
In Triangle ABC, Cos B = (9/12) find Sin B.

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mathematicalpro
 3 years ago
Best ResponseYou've already chosen the best response.1cos = Adjacent/Hypotenuse for finding the third side use pythagorus theorem so,AC^2 =AB^2BC^2 = 12^29^2 = 14481 =63 AC = root 63 AC = 7.9 sinB = Opposite/hypotenuse = 7.9/12

okayimhere
 3 years ago
Best ResponseYou've already chosen the best response.0I'm still pretty unfamiliar with SOHCAHTOA.. I am trying to learn it though...

nikhilchabe
 3 years ago
Best ResponseYou've already chosen the best response.0since cosB=9/12.sinB(opp side/hyp=root 63/12..

okayimhere
 3 years ago
Best ResponseYou've already chosen the best response.0Oh, okay, thankyou guys,[;
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