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okayimhere

  • 4 years ago

In Triangle ABC, Cos B = (9/12) find Sin B.

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  1. okayimhere
    • 4 years ago
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  2. estudier
    • 4 years ago
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    SOHCAHTOA/Pythagorus

  3. estudier
    • 4 years ago
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    U know SOHCAHTOA?

  4. mathematicalpro
    • 4 years ago
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    cos = Adjacent/Hypotenuse for finding the third side use pythagorus theorem so,AC^2 =AB^2-BC^2 = 12^2-9^2 = 144-81 =63 AC = root 63 AC = 7.9 sinB = Opposite/hypotenuse = 7.9/12

  5. okayimhere
    • 4 years ago
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    I'm still pretty unfamiliar with SOHCAHTOA.. I am trying to learn it though...

  6. nikhilchabe
    • 4 years ago
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    since cosB=9/12.sinB(opp side/hyp=root 63/12..

  7. okayimhere
    • 4 years ago
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    Oh, okay, thankyou guys,[;

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