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mathmonster Group TitleBest ResponseYou've already chosen the best response.1
I am writingit now
 3 years ago

mathmonster Group TitleBest ResponseYou've already chosen the best response.1
\[\int\limits_{2}^{4} \left(\begin{matrix}dx \\ /x(lnx)^2\end{matrix}\right)\]
 3 years ago

mathmonster Group TitleBest ResponseYou've already chosen the best response.1
that slash means division
 3 years ago

abtrehearn Group TitleBest ResponseYou've already chosen the best response.1
Let u = ln x, du = dx/x, and substitute into the original integral to reduce it to something more recognizable.
 3 years ago

mathmonster Group TitleBest ResponseYou've already chosen the best response.1
so, let = 1nx, okay let me try that, cause i have been letting u = (lnx)^2 and its been a nightmare
 3 years ago

abtrehearn Group TitleBest ResponseYou've already chosen the best response.1
I think that plain ln x for u will be munc less of a nightmare.
 3 years ago

mathmonster Group TitleBest ResponseYou've already chosen the best response.1
so in did that and got so far u^1/1
 3 years ago

abtrehearn Group TitleBest ResponseYou've already chosen the best response.1
That's the same as\[\int\limits_{}^{}du/u.\]
 3 years ago

abtrehearn Group TitleBest ResponseYou've already chosen the best response.1
Familiar?
 3 years ago

abtrehearn Group TitleBest ResponseYou've already chosen the best response.1
Get it back to original x and you're done.
 3 years ago

mathmonster Group TitleBest ResponseYou've already chosen the best response.1
i am still stuck at this part: \[\int\limits_{2}^{4} du/u^2\]
 3 years ago

mathmonster Group TitleBest ResponseYou've already chosen the best response.1
i got it
 3 years ago

abtrehearn Group TitleBest ResponseYou've already chosen the best response.1
Power formula. Rewrite as\[\int\limits_{}^{}u^{2}du\]
 3 years ago
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