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anonymous
 4 years ago
I am trying to get the integral
anonymous
 4 years ago
I am trying to get the integral

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{2}^{4} \left(\begin{matrix}dx \\ /x(lnx)^2\end{matrix}\right)\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0that slash means division

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Let u = ln x, du = dx/x, and substitute into the original integral to reduce it to something more recognizable.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so, let = 1nx, okay let me try that, cause i have been letting u = (lnx)^2 and its been a nightmare

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I think that plain ln x for u will be munc less of a nightmare.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so in did that and got so far u^1/1

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0That's the same as\[\int\limits_{}^{}du/u.\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Get it back to original x and you're done.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i am still stuck at this part: \[\int\limits_{2}^{4} du/u^2\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Power formula. Rewrite as\[\int\limits_{}^{}u^{2}du\]
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