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mathmonster

  • 4 years ago

I am trying to get the integral

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  1. mathmonster
    • 4 years ago
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    I am writingit now

  2. mathmonster
    • 4 years ago
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    \[\int\limits_{2}^{4} \left(\begin{matrix}dx \\ /x(lnx)^2\end{matrix}\right)\]

  3. mathmonster
    • 4 years ago
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    that slash means division

  4. abtrehearn
    • 4 years ago
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    Let u = ln x, du = dx/x, and substitute into the original integral to reduce it to something more recognizable.

  5. mathmonster
    • 4 years ago
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    so, let = 1nx, okay let me try that, cause i have been letting u = (lnx)^2 and its been a nightmare

  6. abtrehearn
    • 4 years ago
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    I think that plain ln x for u will be munc less of a nightmare.

  7. mathmonster
    • 4 years ago
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    so in did that and got so far u^-1/-1

  8. abtrehearn
    • 4 years ago
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    That's the same as\[-\int\limits_{}^{}du/u.\]

  9. abtrehearn
    • 4 years ago
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    Familiar?

  10. mathmonster
    • 4 years ago
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    yup

  11. abtrehearn
    • 4 years ago
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    Get it back to original x and you're done.

  12. mathmonster
    • 4 years ago
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    i am still stuck at this part: \[\int\limits_{2}^{4} du/u^2\]

  13. mathmonster
    • 4 years ago
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    i got it

  14. abtrehearn
    • 4 years ago
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    Power formula. Rewrite as\[\int\limits_{}^{}u^{-2}du\]

  15. abtrehearn
    • 4 years ago
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    :^)

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