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crisis111

  • 3 years ago

Bob has 5 more dimes than quarters. He has $3.30. How many of each coins does he have.

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  1. saifoo.khan
    • 3 years ago
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    i did one before!

  2. crisis111
    • 3 years ago
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    On my other question? Its not appearing.

  3. saifoo.khan
    • 3 years ago
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    He got 13 dimes, and 8 quatrers!

  4. crisis111
    • 3 years ago
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    And how did you get to that?

  5. espinozagabe
    • 3 years ago
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    He has 13 dimes, and 8 quarters.

  6. espinozagabe
    • 3 years ago
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    And someone else already answered....

  7. saifoo.khan
    • 3 years ago
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    Lol, and someone copied! jk jk

  8. crisis111
    • 3 years ago
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    Haha but how did you get to your answer ?

  9. saifoo.khan
    • 3 years ago
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    \[\Huge My-Mind-works!\]

  10. saifoo.khan
    • 3 years ago
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    \[means..... \Huge Mentally!\]

  11. crisis111
    • 3 years ago
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    this doesnt help much. lol

  12. espinozagabe
    • 3 years ago
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    I got to my answer by just being intuitive. Meaning I just thought about it and even counted on my fingers lol. Then I got my answer.

  13. mojo872
    • 3 years ago
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    It can be solved with algebra. Number of quarters = q and number of dimes = d. We have, from the question: d = q+5 (there are five more dimes than quarters), and 10d + 25q = 330 (total amount of money = $3.30, or 330 cents) Putting them together: 10(q+5) +25q = 330 35q + 50 = 330 35q = 280 Therefore q=8, and d=13, as stated above.

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