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crisis111
 3 years ago
Bob has 5 more dimes than quarters. He has $3.30. How many of each coins does he have.
crisis111
 3 years ago
Bob has 5 more dimes than quarters. He has $3.30. How many of each coins does he have.

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crisis111
 3 years ago
Best ResponseYou've already chosen the best response.0On my other question? Its not appearing.

saifoo.khan
 3 years ago
Best ResponseYou've already chosen the best response.0He got 13 dimes, and 8 quatrers!

crisis111
 3 years ago
Best ResponseYou've already chosen the best response.0And how did you get to that?

espinozagabe
 3 years ago
Best ResponseYou've already chosen the best response.0He has 13 dimes, and 8 quarters.

espinozagabe
 3 years ago
Best ResponseYou've already chosen the best response.0And someone else already answered....

saifoo.khan
 3 years ago
Best ResponseYou've already chosen the best response.0Lol, and someone copied! jk jk

crisis111
 3 years ago
Best ResponseYou've already chosen the best response.0Haha but how did you get to your answer ?

saifoo.khan
 3 years ago
Best ResponseYou've already chosen the best response.0\[\Huge MyMindworks!\]

saifoo.khan
 3 years ago
Best ResponseYou've already chosen the best response.0\[means..... \Huge Mentally!\]

crisis111
 3 years ago
Best ResponseYou've already chosen the best response.0this doesnt help much. lol

espinozagabe
 3 years ago
Best ResponseYou've already chosen the best response.0I got to my answer by just being intuitive. Meaning I just thought about it and even counted on my fingers lol. Then I got my answer.

mojo872
 3 years ago
Best ResponseYou've already chosen the best response.1It can be solved with algebra. Number of quarters = q and number of dimes = d. We have, from the question: d = q+5 (there are five more dimes than quarters), and 10d + 25q = 330 (total amount of money = $3.30, or 330 cents) Putting them together: 10(q+5) +25q = 330 35q + 50 = 330 35q = 280 Therefore q=8, and d=13, as stated above.
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