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Bob has 5 more dimes than quarters. He has $3.30. How many of each coins does he have.
 2 years ago
 2 years ago
Bob has 5 more dimes than quarters. He has $3.30. How many of each coins does he have.
 2 years ago
 2 years ago

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crisis111Best ResponseYou've already chosen the best response.0
On my other question? Its not appearing.
 2 years ago

saifoo.khanBest ResponseYou've already chosen the best response.0
He got 13 dimes, and 8 quatrers!
 2 years ago

crisis111Best ResponseYou've already chosen the best response.0
And how did you get to that?
 2 years ago

espinozagabeBest ResponseYou've already chosen the best response.0
He has 13 dimes, and 8 quarters.
 2 years ago

espinozagabeBest ResponseYou've already chosen the best response.0
And someone else already answered....
 2 years ago

saifoo.khanBest ResponseYou've already chosen the best response.0
Lol, and someone copied! jk jk
 2 years ago

crisis111Best ResponseYou've already chosen the best response.0
Haha but how did you get to your answer ?
 2 years ago

saifoo.khanBest ResponseYou've already chosen the best response.0
\[\Huge MyMindworks!\]
 2 years ago

saifoo.khanBest ResponseYou've already chosen the best response.0
\[means..... \Huge Mentally!\]
 2 years ago

crisis111Best ResponseYou've already chosen the best response.0
this doesnt help much. lol
 2 years ago

espinozagabeBest ResponseYou've already chosen the best response.0
I got to my answer by just being intuitive. Meaning I just thought about it and even counted on my fingers lol. Then I got my answer.
 2 years ago

mojo872Best ResponseYou've already chosen the best response.1
It can be solved with algebra. Number of quarters = q and number of dimes = d. We have, from the question: d = q+5 (there are five more dimes than quarters), and 10d + 25q = 330 (total amount of money = $3.30, or 330 cents) Putting them together: 10(q+5) +25q = 330 35q + 50 = 330 35q = 280 Therefore q=8, and d=13, as stated above.
 2 years ago
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