A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
In a state lottery, a player fills out a ticket by choosing five "regular" numbers from 1 to 45, without repetition, and one PowerBall number from 1 to 45. The goal is to match the numbers with those drawn at random at the end of the week. The regular numbers chosen do not have to be in the same order as those drawn.
How many different ways are there to fill out a ticket?
anonymous
 4 years ago
In a state lottery, a player fills out a ticket by choosing five "regular" numbers from 1 to 45, without repetition, and one PowerBall number from 1 to 45. The goal is to match the numbers with those drawn at random at the end of the week. The regular numbers chosen do not have to be in the same order as those drawn. How many different ways are there to fill out a ticket?

This Question is Closed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.045C5 * 45C1 where: \[nCr = \left(\begin{matrix}n \\ r\end{matrix}\right) = \frac{n!}{r!(nr)!}\] you want to calculate: \[\left(\begin{matrix}45 \\ 5\end{matrix}\right)*\left(\begin{matrix}45 \\ 1\end{matrix}\right)\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0nCr is read "n choose r" Its how many ways you can choose r things from a group of n objects.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Thank you so much!! :) Big help!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0How would I solve the problem if it said: A player wins the jackpot by matching all five regular numbers plus the PowerBall number. This is called "Match 5+1." How many different ways are there to fill out a ticket that is a "match 5+1" winner? What is the probability of the event "Match 5+1"?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0The number of ways to fill out the ticket would be the same (assuming there are still 45 numbers to choose from). As for the probability of winning, once you get the answer to the first problem (lets call it CAT for lulz), it would be: \[P(winning) = \frac{1}{CAT}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so what's the difference between this question and the last one i asked you? there has to be a difference

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0There isnt a difference that i can tell. In the first one you wanted to know how many ways you can fill out a ticket where you have to pick 5 numbers from 45 and one bonus number from 45. Its the same thing in the second problem. You're filling out the same type of ticket.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0The only way there would be a difference is if you had to match the order of the numbers. Then there is major difference.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok but for probability, shouldn't it be a fraction? Ex: 1/4 probability?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0it will be, the answer will be 1/(some big number), which logically makes sense, because the probability of winning the lottery should be really really low.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Thanks so much for all your help! :)
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.