Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

I need a Journal Answer/Written Answer for this one: How do the Triangle-Angle Bisector Theorem and the Angle Bisector Theorem differ?

See more answers at
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly


Get your free account and access expert answers to this and thousands of other questions

U asked this yesterday and I said that I thought they were the same thing.
Yeah I know. But I don't think they are.
Why do you think that?

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

Someone else mentioned something about the Triangle-Angle Bisector Theorem including an angle bisector.
Hmm. I'll think about it more.
Your probably right though. lol
I'll go with your answer. :)
I'm reasonably sure about it, let's say.
I'll go with your answer. :)
So you were pretty much correct. The difference is that the angle bisector theorem can be applied to any angle. However when that theorem is applied in a triangle it divides it into two different segments, and the corresponding sides in each of the two segments are then proportional to each other.
Ah, OK, one is a special case of the other. Thanks for coming back.
Well I wanted to let you know the answer as well. lol

Not the answer you are looking for?

Search for more explanations.

Ask your own question