DOES THERE EXIST A SET OF REAL NUMBERS A, B AND C FOR WHICH THE FUNCTION
TAN-1(X) X = 0
F(X)= AX^2 + BX + C, 0 = 2
IS DIFFERENTIABLE (I.E. EVERYWHERE DIFFERENTIABLE)? EXPLAIN WHY OR WHY NOT. (HERE TAN-1(X) DENOTES THE INVERSE
OF THE TANGENT FUNCTION.) (From Unit 1 Exam 1 Question 5)(Sorry for the notation).
According to the solutions, I don't understand how after we take the inverse of tan of 0 we equate that with C automatically.
Also I don't get how at x = 0 the derivative of 5x^2 + x is 5* 0+1=1.

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