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09eisenfisz
 4 years ago
Evaluate the indefinite integral :
I= INTEGRAL(x^8/(36−x^2)^(11/2) dx)
HINT: use a trigonometric substitution, then use sinx/cosx=tanx and 1/cosx=secx.
09eisenfisz
 4 years ago
Evaluate the indefinite integral : I= INTEGRAL(x^8/(36−x^2)^(11/2) dx) HINT: use a trigonometric substitution, then use sinx/cosx=tanx and 1/cosx=secx.

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Jennylee
 4 years ago
Best ResponseYou've already chosen the best response.0This should help. Make sure to click the "show steps" button. http://www.wolframalpha.com/input/?i=Int+%28x^8%2F%2836%E2%88%92x^2%29^%2811%2F2%29+dx%29+
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