anonymous
  • anonymous
Find the area of the shaded portion in the equilateral triangle with sides 6. (assuming the central point of each arc is its corresponding vertex)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
1 Attachment
anonymous
  • anonymous
btw its not a thong soo no ideas!!
saifoo.khan
  • saifoo.khan
Lol @ thongs.

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More answers

saifoo.khan
  • saifoo.khan
\[\Huge Hasirrrr!\]
anonymous
  • anonymous
yup i m here
anonymous
  • anonymous
apply sine rule a=1/2(6)(6)sin60 then
saifoo.khan
  • saifoo.khan
aera of triangle = 7.8
anonymous
  • anonymous
find area of sector A of sector= (60/360)(pie)(3)^2 multiply it by three
anonymous
  • anonymous
subrat it from the A u get from the sine rule
saifoo.khan
  • saifoo.khan
lol, im getting 3 different answers!
anonymous
  • anonymous
apply sine rule a=1/2(6)(6)sin60 then find area of sector A of sector= (60/360)(pie)(3)^2 multiply it by three ans=15.58-3(4.71)=1.443
anonymous
  • anonymous
hey hello saif
saifoo.khan
  • saifoo.khan
lol, hi honey.. supp?
anonymous
  • anonymous
nm u?
saifoo.khan
  • saifoo.khan
same here, nm.
anonymous
  • anonymous
hi..........saif i solved the question koi medal to do
anonymous
  • anonymous
Looks like 3 sectors of a circle. Area of a sector of a circle is: area of circle * degrees of sector/360 the sector has 60 degrees because the triangle is equilateral. Area of circle = 9π Area of 3 sectors: 9π * 60/360 * 3 = 4.5π Area of shaded part = area of triangle - 4.5π area of triangle = 1/2(6)(6)(sin 60) = 15.5884573 4.5π = 14.1371669 15.5884573 - 14.1371669 = 1.4512904 Hope that helps
anonymous
  • anonymous
ummm guys u know that theres a thing cxalled group chat below ur screen lolz
anonymous
  • anonymous
sorry terr this is more coool
saifoo.khan
  • saifoo.khan
Lol @ terri & honey!
saifoo.khan
  • saifoo.khan
@hashir, a medal for a medal..
anonymous
  • anonymous
i think u have one
saifoo.khan
  • saifoo.khan
i have two!

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