terricherri
Find the area of the shaded portion in the equilateral triangle with sides 6.
(assuming the central point of each arc is its corresponding vertex)
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terricherri
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terricherri
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btw its not a thong soo no ideas!!
saifoo.khan
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Lol @ thongs.
saifoo.khan
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\[\Huge Hasirrrr!\]
Hashir
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yup i m here
Hashir
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apply sine rule
a=1/2(6)(6)sin60 then
saifoo.khan
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aera of triangle = 7.8
Hashir
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find area of sector A of sector= (60/360)(pie)(3)^2
multiply it by three
Hashir
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subrat it from the A u get from the sine rule
saifoo.khan
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lol, im getting 3 different answers!
Hashir
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apply sine rule
a=1/2(6)(6)sin60 then
find area of sector A of sector= (60/360)(pie)(3)^2
multiply it by three
ans=15.58-3(4.71)=1.443
Honey_Girl
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hey hello saif
saifoo.khan
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lol, hi honey.. supp?
Honey_Girl
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nm u?
saifoo.khan
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same here, nm.
Hashir
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hi..........saif i solved the question koi medal to do
anhhuyalex
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Looks like 3 sectors of a circle.
Area of a sector of a circle is: area of circle * degrees of sector/360
the sector has 60 degrees because the triangle is equilateral.
Area of circle = 9π
Area of 3 sectors: 9π * 60/360 * 3 = 4.5π
Area of shaded part = area of triangle - 4.5π
area of triangle = 1/2(6)(6)(sin 60) = 15.5884573
4.5π = 14.1371669
15.5884573 - 14.1371669 = 1.4512904
Hope that helps
terricherri
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ummm guys u know that theres a thing cxalled group chat below ur screen lolz
Honey_Girl
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sorry terr this is more coool
saifoo.khan
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Lol @ terri & honey!
saifoo.khan
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@hashir, a medal for a medal..
Hashir
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i think u have one
saifoo.khan
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i have two!