Find the area of the shaded portion in the equilateral triangle with sides 6. (assuming the central point of each arc is its corresponding vertex)

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Find the area of the shaded portion in the equilateral triangle with sides 6. (assuming the central point of each arc is its corresponding vertex)

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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btw its not a thong soo no ideas!!
Lol @ thongs.

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\[\Huge Hasirrrr!\]
yup i m here
apply sine rule a=1/2(6)(6)sin60 then
aera of triangle = 7.8
find area of sector A of sector= (60/360)(pie)(3)^2 multiply it by three
subrat it from the A u get from the sine rule
lol, im getting 3 different answers!
apply sine rule a=1/2(6)(6)sin60 then find area of sector A of sector= (60/360)(pie)(3)^2 multiply it by three ans=15.58-3(4.71)=1.443
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nm u?
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hi..........saif i solved the question koi medal to do
Looks like 3 sectors of a circle. Area of a sector of a circle is: area of circle * degrees of sector/360 the sector has 60 degrees because the triangle is equilateral. Area of circle = 9π Area of 3 sectors: 9π * 60/360 * 3 = 4.5π Area of shaded part = area of triangle - 4.5π area of triangle = 1/2(6)(6)(sin 60) = 15.5884573 4.5π = 14.1371669 15.5884573 - 14.1371669 = 1.4512904 Hope that helps
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sorry terr this is more coool
Lol @ terri & honey!
@hashir, a medal for a medal..
i think u have one
i have two!

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