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Akshay_Budhkar
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let w=e^{(i*pie)/3} and a,b,c,x,y,z be non zero complex numbers such that
a+b+c=x
a+bw+cw^2=y
a+bw^2+cw=z
thn the value of ([x]^2+[y]^2+[z]^2)/([a]^2+[b]^2+[c]^2) is???
where [q] is mod q...
 3 years ago
 3 years ago
Akshay_Budhkar Group Title
let w=e^{(i*pie)/3} and a,b,c,x,y,z be non zero complex numbers such that a+b+c=x a+bw+cw^2=y a+bw^2+cw=z thn the value of ([x]^2+[y]^2+[z]^2)/([a]^2+[b]^2+[c]^2) is??? where [q] is mod q...
 3 years ago
 3 years ago

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Akshay_Budhkar Group TitleBest ResponseYou've already chosen the best response.1
question from iit 2011
 3 years ago

Akshay_Budhkar Group TitleBest ResponseYou've already chosen the best response.1
w is cube root of unity i believe.. the complex cube root of unity
 3 years ago

estudier Group TitleBest ResponseYou've already chosen the best response.0
What's iit?
 3 years ago

Ishaan94 Group TitleBest ResponseYou've already chosen the best response.1
yeah it is
 3 years ago

Akshay_Budhkar Group TitleBest ResponseYou've already chosen the best response.1
IITindian institute of technology
 3 years ago

Ishaan94 Group TitleBest ResponseYou've already chosen the best response.1
it is the best institute in india for engineering
 3 years ago

estudier Group TitleBest ResponseYou've already chosen the best response.0
Ok, thks, I didn't know...
 3 years ago

estudier Group TitleBest ResponseYou've already chosen the best response.0
Not really an engineering question:)
 3 years ago

Ishaan94 Group TitleBest ResponseYou've already chosen the best response.1
yeah but after 12 th we have to give entrance test jee( i don't know the full form) it's from that
 3 years ago

Akshay_Budhkar Group TitleBest ResponseYou've already chosen the best response.1
i had solved the ques using a short cut to save time
 3 years ago

Ishaan94 Group TitleBest ResponseYou've already chosen the best response.1
jee to get into iit
 3 years ago

Akshay_Budhkar Group TitleBest ResponseYou've already chosen the best response.1
jeejoint entrance exam
 3 years ago

estudier Group TitleBest ResponseYou've already chosen the best response.0
Mind u, maybe u have to be an engineer to solve it..
 3 years ago

Ishaan94 Group TitleBest ResponseYou've already chosen the best response.1
oh well let me try it well i get confused jee e for entrance or engineering lol
 3 years ago

Akshay_Budhkar Group TitleBest ResponseYou've already chosen the best response.1
just take a=b=c=1 and get x,y,z and ur done!!!!! lol!!!! but now i want the technical answer
 3 years ago

Ishaan94 Group TitleBest ResponseYou've already chosen the best response.1
well 3a = x+y+z
 3 years ago

Akshay_Budhkar Group TitleBest ResponseYou've already chosen the best response.1
that did get me 4 marks in the paper..substitution
 3 years ago

Akshay_Budhkar Group TitleBest ResponseYou've already chosen the best response.1
right add all the three. 1+w+wsquare is 0
 3 years ago

Akshay_Budhkar Group TitleBest ResponseYou've already chosen the best response.1
any suggestions estudier??? ishaan i cant find a way ahead of it..
 3 years ago

Ishaan94 Group TitleBest ResponseYou've already chosen the best response.1
me too but wait a minute
 3 years ago

estudier Group TitleBest ResponseYou've already chosen the best response.0
I don't like this kind of problems..:
 3 years ago

Ishaan94 Group TitleBest ResponseYou've already chosen the best response.1
well 3a = x + y+z
 3 years ago

Akshay_Budhkar Group TitleBest ResponseYou've already chosen the best response.1
dude do u remeber (a+b+c)(a+bw+cw^2)(a+bw^2+cw)=?????? its a formula.. i am not remembering
 3 years ago

Ishaan94 Group TitleBest ResponseYou've already chosen the best response.1
but x^2 makes the possible minus vanish and hence x^2 + y^2+x^2 = x^2 + y^2 + z^2 \ just wait like 20 sec
 3 years ago

Ishaan94 Group TitleBest ResponseYou've already chosen the best response.1
a^2 + b^2 +c^2 ab +ac cb
 3 years ago

Ishaan94 Group TitleBest ResponseYou've already chosen the best response.1
not including (a+b+c)
 3 years ago

Akshay_Budhkar Group TitleBest ResponseYou've already chosen the best response.1
ac dude.. all signs were same no?
 3 years ago

Ishaan94 Group TitleBest ResponseYou've already chosen the best response.1
well including a+b+c it becomes x^3 + y^3 +z^3 3xyz x=a y=b z=c
 3 years ago

Akshay_Budhkar Group TitleBest ResponseYou've already chosen the best response.1
ya right.. that was d formula..
 3 years ago

Ishaan94 Group TitleBest ResponseYou've already chosen the best response.1
lets do it x^2 + y^2 +z^2 you find y while i find x^2 and z^2
 3 years ago

Akshay_Budhkar Group TitleBest ResponseYou've already chosen the best response.1
ok.. but i believe it is not so lenthy dude.. we get jus 3 minutes for a problem.. there must be some trick
 3 years ago

Ishaan94 Group TitleBest ResponseYou've already chosen the best response.1
your right
 3 years ago

Ishaan94 Group TitleBest ResponseYou've already chosen the best response.1
hey (x + y+z) ^2 = x2 +y2 + z2 +2xy + 2xz+2yz
 3 years ago

Ishaan94 Group TitleBest ResponseYou've already chosen the best response.1
x + y +z = 3a
 3 years ago

estudier Group TitleBest ResponseYou've already chosen the best response.0
hey (x + y+z) ^2 = x2 +y2 + z2 +2xy + 2xz+2yz I saw that in your puzzle from yesterday...
 3 years ago

Ishaan94 Group TitleBest ResponseYou've already chosen the best response.1
9a^2 = x^2 + y^2 +z^2 +2xy + 2zy +2xz
 3 years ago

Akshay_Budhkar Group TitleBest ResponseYou've already chosen the best response.1
right
 3 years ago

Ishaan94 Group TitleBest ResponseYou've already chosen the best response.1
so ^2 make minus sign vanish
 3 years ago

Ishaan94 Group TitleBest ResponseYou've already chosen the best response.1
it implies x^2 = x^2
 3 years ago

Akshay_Budhkar Group TitleBest ResponseYou've already chosen the best response.1
ofcourse.. its given just to confuse mod is not needed
 3 years ago

Ishaan94 Group TitleBest ResponseYou've already chosen the best response.1
ve sign don't exist in squares
 3 years ago

Ishaan94 Group TitleBest ResponseYou've already chosen the best response.1
letme solve a lil
 3 years ago

Akshay_Budhkar Group TitleBest ResponseYou've already chosen the best response.1
i believe iit didnt want us to use the substitution method.... coz i have not found a way out till now after 3 months i gae the exam
 3 years ago

Akshay_Budhkar Group TitleBest ResponseYou've already chosen the best response.1
@face give it a try
 3 years ago

Ishaan94 Group TitleBest ResponseYou've already chosen the best response.1
damn iit never let someone enter easily
 3 years ago

Akshay_Budhkar Group TitleBest ResponseYou've already chosen the best response.1
but the substitution method is alays there!!!!! lol!! the only weak point of iit jee.. lol!!!
 3 years ago

Ishaan94 Group TitleBest ResponseYou've already chosen the best response.1
well what was the options
 3 years ago

Akshay_Budhkar Group TitleBest ResponseYou've already chosen the best response.1
*always
 3 years ago

Akshay_Budhkar Group TitleBest ResponseYou've already chosen the best response.1
its an integer type ques 0 to 9 all options
 3 years ago

Ishaan94 Group TitleBest ResponseYou've already chosen the best response.1
aahhhh scary
 3 years ago

Akshay_Budhkar Group TitleBest ResponseYou've already chosen the best response.1
generally we mark 2 if we dun kno... 40 percent of ques hav ans 2 lol!!!
 3 years ago

Ishaan94 Group TitleBest ResponseYou've already chosen the best response.1
Ok , Here I go
 3 years ago

Akshay_Budhkar Group TitleBest ResponseYou've already chosen the best response.1
ya go go bye. lol js kidding
 3 years ago

Ishaan94 Group TitleBest ResponseYou've already chosen the best response.1
Okay Here we Have \[x = a+b+c\] \[y =a+bw+cw^2\] \[z = a + bw^2+cw\] Now we have to find \[\large{\frac{x^2 + y^2 + z^2 }{a^2 + b^2 +c^2}}\] \[z^2 = z*(conj.z)\] \[conj.y = a+bw^2 +cw\] \[conj.z = a+bw+cw^2\] Okay So we have now \[\frac{(a+b+c)^2 + 2(a + bw+cw^2)(a+bw^2+cw)}{a^2+b^2+c^2}\] \[\frac{3(a^2+b^2+c^2) +2(ab+bc+ac)  2(ab+bc+ac)}{a^2+b^2+c^2}\]\[3\] Beautiful Solution : )
 3 years ago

Akshay_Budhkar Group TitleBest ResponseYou've already chosen the best response.1
Beauty
 3 years ago
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