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arjunmit
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Why does a open loop transfer function has a pole at origin ??
 2 years ago
 2 years ago
arjunmit Group Title
Why does a open loop transfer function has a pole at origin ??
 2 years ago
 2 years ago

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ncos Group TitleBest ResponseYou've already chosen the best response.0
Only if it involves integration (which would put an s in the denominator: \[H(s)=1/s\] A pole will occur when the denominator is zero, which will occur when s=0.
 2 years ago
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