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mathtard

  • 3 years ago

Can anyone please help me with this problem? \[f(t)\sqrt{t^2+1}\] find the function if it exists

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  1. estudier
    • 3 years ago
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    I suppose the function sqrt(t^2+1) does indeed exist...

  2. mathtard
    • 3 years ago
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    but how do you find the function?

  3. estudier
    • 3 years ago
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    U appear to have found it, it's right there...

  4. mathtard
    • 3 years ago
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    That is the question

  5. estudier
    • 3 years ago
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    U are saying find the function but u are telling me what the function is?????

  6. mathtard
    • 3 years ago
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    that is how the problem is written. ???????

  7. estudier
    • 3 years ago
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    I dont understand what u want me to do, neither does anybody else.

  8. mathtard
    • 3 years ago
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    well i am just writing the problem the way it is written.

  9. mathtard
    • 3 years ago
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    oops find the function value if it exists

  10. mathtard
    • 3 years ago
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    sorry i thought I wrote value .

  11. estudier
    • 3 years ago
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    The only thing I can say about the function is that it must be positive by definition. Else you have to provide a t to enable calculation of a value for that particular value of t.

  12. Alchemista
    • 3 years ago
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    \[f(t)\sqrt{t^2+1} \cdot \sqrt{t^2+1}^{-1} = f(t)\] which is the "value" of the function at t

  13. mathtard
    • 3 years ago
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    it says f(0)= ??????

  14. estudier
    • 3 years ago
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    That-s better....

  15. mathtard
    • 3 years ago
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    sorry about that estudier.

  16. Alchemista
    • 3 years ago
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    So you mean \[ f(t) = \sqrt{t^2+1}\]\[\text{Find $f(0)$}\]

  17. estudier
    • 3 years ago
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    1

  18. Alchemista
    • 3 years ago
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    \[f(0) = \sqrt{(0)^2+1} = \sqrt{1} = 1\]

  19. mathtard
    • 3 years ago
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    Thank you!!!!

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