anonymous
  • anonymous
Can anyone please help me with this problem? \[f(t)\sqrt{t^2+1}\] find the function if it exists
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
I suppose the function sqrt(t^2+1) does indeed exist...
anonymous
  • anonymous
but how do you find the function?
anonymous
  • anonymous
U appear to have found it, it's right there...

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anonymous
  • anonymous
That is the question
anonymous
  • anonymous
U are saying find the function but u are telling me what the function is?????
anonymous
  • anonymous
that is how the problem is written. ???????
anonymous
  • anonymous
I dont understand what u want me to do, neither does anybody else.
anonymous
  • anonymous
well i am just writing the problem the way it is written.
anonymous
  • anonymous
oops find the function value if it exists
anonymous
  • anonymous
sorry i thought I wrote value .
anonymous
  • anonymous
The only thing I can say about the function is that it must be positive by definition. Else you have to provide a t to enable calculation of a value for that particular value of t.
anonymous
  • anonymous
\[f(t)\sqrt{t^2+1} \cdot \sqrt{t^2+1}^{-1} = f(t)\] which is the "value" of the function at t
anonymous
  • anonymous
it says f(0)= ??????
anonymous
  • anonymous
That-s better....
anonymous
  • anonymous
sorry about that estudier.
anonymous
  • anonymous
So you mean \[ f(t) = \sqrt{t^2+1}\]\[\text{Find $f(0)$}\]
anonymous
  • anonymous
1
anonymous
  • anonymous
\[f(0) = \sqrt{(0)^2+1} = \sqrt{1} = 1\]
anonymous
  • anonymous
Thank you!!!!

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