## anonymous 5 years ago Can anyone please help me with this problem? $f(t)\sqrt{t^2+1}$ find the function if it exists

1. anonymous

I suppose the function sqrt(t^2+1) does indeed exist...

2. anonymous

but how do you find the function?

3. anonymous

U appear to have found it, it's right there...

4. anonymous

That is the question

5. anonymous

U are saying find the function but u are telling me what the function is?????

6. anonymous

that is how the problem is written. ???????

7. anonymous

I dont understand what u want me to do, neither does anybody else.

8. anonymous

well i am just writing the problem the way it is written.

9. anonymous

oops find the function value if it exists

10. anonymous

sorry i thought I wrote value .

11. anonymous

The only thing I can say about the function is that it must be positive by definition. Else you have to provide a t to enable calculation of a value for that particular value of t.

12. anonymous

$f(t)\sqrt{t^2+1} \cdot \sqrt{t^2+1}^{-1} = f(t)$ which is the "value" of the function at t

13. anonymous

it says f(0)= ??????

14. anonymous

That-s better....

15. anonymous

16. anonymous

So you mean $f(t) = \sqrt{t^2+1}$$\text{Find f(0)}$

17. anonymous

1

18. anonymous

$f(0) = \sqrt{(0)^2+1} = \sqrt{1} = 1$

19. anonymous

Thank you!!!!