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mathtard
Group Title
Can anyone please help me with this problem?
\[f(t)\sqrt{t^2+1}\]
find the function if it exists
 3 years ago
 3 years ago
mathtard Group Title
Can anyone please help me with this problem? \[f(t)\sqrt{t^2+1}\] find the function if it exists
 3 years ago
 3 years ago

This Question is Closed

estudier Group TitleBest ResponseYou've already chosen the best response.2
I suppose the function sqrt(t^2+1) does indeed exist...
 3 years ago

mathtard Group TitleBest ResponseYou've already chosen the best response.0
but how do you find the function?
 3 years ago

estudier Group TitleBest ResponseYou've already chosen the best response.2
U appear to have found it, it's right there...
 3 years ago

mathtard Group TitleBest ResponseYou've already chosen the best response.0
That is the question
 3 years ago

estudier Group TitleBest ResponseYou've already chosen the best response.2
U are saying find the function but u are telling me what the function is?????
 3 years ago

mathtard Group TitleBest ResponseYou've already chosen the best response.0
that is how the problem is written. ???????
 3 years ago

estudier Group TitleBest ResponseYou've already chosen the best response.2
I dont understand what u want me to do, neither does anybody else.
 3 years ago

mathtard Group TitleBest ResponseYou've already chosen the best response.0
well i am just writing the problem the way it is written.
 3 years ago

mathtard Group TitleBest ResponseYou've already chosen the best response.0
oops find the function value if it exists
 3 years ago

mathtard Group TitleBest ResponseYou've already chosen the best response.0
sorry i thought I wrote value .
 3 years ago

estudier Group TitleBest ResponseYou've already chosen the best response.2
The only thing I can say about the function is that it must be positive by definition. Else you have to provide a t to enable calculation of a value for that particular value of t.
 3 years ago

Alchemista Group TitleBest ResponseYou've already chosen the best response.0
\[f(t)\sqrt{t^2+1} \cdot \sqrt{t^2+1}^{1} = f(t)\] which is the "value" of the function at t
 3 years ago

mathtard Group TitleBest ResponseYou've already chosen the best response.0
it says f(0)= ??????
 3 years ago

estudier Group TitleBest ResponseYou've already chosen the best response.2
Thats better....
 3 years ago

mathtard Group TitleBest ResponseYou've already chosen the best response.0
sorry about that estudier.
 3 years ago

Alchemista Group TitleBest ResponseYou've already chosen the best response.0
So you mean \[ f(t) = \sqrt{t^2+1}\]\[\text{Find $f(0)$}\]
 3 years ago

Alchemista Group TitleBest ResponseYou've already chosen the best response.0
\[f(0) = \sqrt{(0)^2+1} = \sqrt{1} = 1\]
 3 years ago

mathtard Group TitleBest ResponseYou've already chosen the best response.0
Thank you!!!!
 3 years ago
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