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polpak
 3 years ago
Best ResponseYou've already chosen the best response.1Typically you have to complete the square, then move the constant term to the left side with your y variable.

polpak
 3 years ago
Best ResponseYou've already chosen the best response.1I'm assuming you're referring to the quadratic function here and not some other function with a vertex.

Sophmoregrad2014
 3 years ago
Best ResponseYou've already chosen the best response.0can you give me an example becuase its on my test tommorow and my teacher cant explain it

polpak
 3 years ago
Best ResponseYou've already chosen the best response.1So lets say you have some quadratic equation in the form: \[y = x^2 + 2x 8\] To write it in vertex form, we need to have something like: \[yy_1 = C(xx_1)^2\] So we need to take the x^2 and the 2x and make something that is just (xx1)^2. To do that, we take half of the coefficient on the x term and square that. So half of 2 is 1, 1 squared is 1. Then we simultaneously add and subtract (adding a 0) that amount out of the equation: \[\implies y = x^2 + 2x + 1  1\  8\] Then we collect out completed square: \[\implies y =(x1)^2  1 8\] Combine the constant parts: \[\implies y = (x1)^2  9\] Then add or subtract the constant part to the other side: \[\implies y+9 = (x1)^2\] That's vertex form and shows that the quadratic has a vertex at (1,9)

bookymb143
 3 years ago
Best ResponseYou've already chosen the best response.0change the parabola equadion from vertex form to standared form

bookymb143
 3 years ago
Best ResponseYou've already chosen the best response.0i think that it because i suck and math

Sophmoregrad2014
 3 years ago
Best ResponseYou've already chosen the best response.0ok so if the equation is: \[3x ^{2} + 4x  7\]
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