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giggles123Best ResponseYou've already chosen the best response.1
working on it give me a sec
 2 years ago

giggles123Best ResponseYou've already chosen the best response.1
sqrt(3a)+16asqrt(3a)===>17sqrt(3a)
 2 years ago

saifoo.khanBest ResponseYou've already chosen the best response.1
why? where does it goes?
 2 years ago

giggles123Best ResponseYou've already chosen the best response.1
sqrt(3a)+8sqrt(12a^(3)) Pull all perfect square roots out from under the radical. In this case, remove the 2a because it is a perfect square. sqrt(3a)+(8*2asqrt(3a)) Multiply 8 by 2a to get 16a. sqrt(3a)+(16a)sqrt(3a) Remove the parentheses around the expression 16a. sqrt(3a)+16asqrt(3a)
 2 years ago

HeroBest ResponseYou've already chosen the best response.0
Yeah, that's the correct answer
 2 years ago

HeroBest ResponseYou've already chosen the best response.0
and the way it should be written...
 2 years ago

HeroBest ResponseYou've already chosen the best response.0
the a goes before the root not after it
 2 years ago

saifoo.khanBest ResponseYou've already chosen the best response.1
the answer is \[\Huge \sqrt{3a}(16a+1)\]
 2 years ago

giggles123Best ResponseYou've already chosen the best response.1
its the same thing in a different form
 2 years ago

HeroBest ResponseYou've already chosen the best response.0
Whose online test are you taking this time?
 2 years ago

saifoo.khanBest ResponseYou've already chosen the best response.1
there is a extra 'a'
 2 years ago

HeroBest ResponseYou've already chosen the best response.0
the right amount of a's are there
 2 years ago

HeroBest ResponseYou've already chosen the best response.0
so if it's the right answer, there could never be an extra a, if there was it would be one a too many and it would be wrong
 2 years ago

saifoo.khanBest ResponseYou've already chosen the best response.1
in the photo u can see, its 16root(3a) a. because of that last a, u cant add them!
 2 years ago

HeroBest ResponseYou've already chosen the best response.0
Yes, you're right, you can't add them...so factoring out the sqrt(3a) was a good step....
 2 years ago
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