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physopholy
 3 years ago
Best ResponseYou've already chosen the best response.2y=3^(x/2) logy=(x/2)log3 1/y(dy/dx)=(1/2)log3 dy/dx=y*(1/2)log3 dy/dx=(3^(x/2))(1/2)log3

101Ryan101
 3 years ago
Best ResponseYou've already chosen the best response.0should be (3^(x/2))(x/2)log3

bnut056
 3 years ago
Best ResponseYou've already chosen the best response.0d/dx(Cx^Ax)=Cx^Ax(Aln(Cx)+AxC/Cx)

bnut056
 3 years ago
Best ResponseYou've already chosen the best response.0d/dx(C^Ax)=C^Ax(Aln(C))

someone1348
 3 years ago
Best ResponseYou've already chosen the best response.0\[f(x)=3^{\frac{x}{2}}=e^{\frac{\ln(3) \times x}{2}}\] \[f'(x)=\frac{\ln(3)}{2} \times e^{\frac{\ln(3) \times x}{2}}=\frac{\ln(3)}{2} \times 3^{\frac{x}{2}}\]

someone1348
 3 years ago
Best ResponseYou've already chosen the best response.0Umm sorry, forgot the minus symbol, just plug it in and you get \[f'(x)= \frac{\ln(3)}{2} \times 3^{ \frac{x}{2}} \]

physopholy
 3 years ago
Best ResponseYou've already chosen the best response.2no, the derivative of C^u is (C^u)(du)(lnC). So, what I did originally, but with ln instead of log. Someone1348's right, too
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