Akshay_Budhkar
  • Akshay_Budhkar
satellite plz help with the probability question!!!!
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
yup
Akshay_Budhkar
  • Akshay_Budhkar
try it hafiz..

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More answers

anonymous
  • anonymous
hello
Akshay_Budhkar
  • Akshay_Budhkar
hello.. i tried it.. no use
anonymous
  • anonymous
link isn't working for me
Akshay_Budhkar
  • Akshay_Budhkar
we can solve here
Akshay_Budhkar
  • Akshay_Budhkar
a rod is divided in 4 parts.. probability that it is a quadrilateral?
anonymous
  • anonymous
ok it is the same problem as last time yes?
Akshay_Budhkar
  • Akshay_Budhkar
yes
anonymous
  • anonymous
not sure what you mean. i meant use the second proof in the paper i sent you. not the volume one, but the line segment one.
anonymous
  • anonymous
start an page 186 at the line "construction of an n-gon will be impossible of AB is longer than 1/2" do you see where i mean?
anonymous
  • anonymous
of course replace n by 4
anonymous
  • anonymous
i am here.
anonymous
  • anonymous
i may be easier to do this in chat, or quicker, but i can write the idea of the proof here. i am just mimicking the proof i sent you in the pfd .
Akshay_Budhkar
  • Akshay_Budhkar
you can come in chat?
anonymous
  • anonymous
you have a "rod" stick whatever and you are going to break it into 4 parts by picking 3 points uniformly at random, and the question is what is the probability that you can make a quadrilateral
Akshay_Budhkar
  • Akshay_Budhkar
yes
anonymous
  • anonymous
you already know the answer is 1/2 so far correct. so we just need the proof
Akshay_Budhkar
  • Akshay_Budhkar
yes
anonymous
  • anonymous
first trick to to say that the rod has length one so we can dispense with ratios
Akshay_Budhkar
  • Akshay_Budhkar
ya
anonymous
  • anonymous
so it looks something like this 0 --------------a-----------------b--------------------------c-------------------------1 where a, b, c are the points chosen at random to break up the rod
anonymous
  • anonymous
now the question is "when would you not get a quadrilateral\"
anonymous
  • anonymous
now i am just reading along what i sent, replacing n by 4
anonymous
  • anonymous
construction of a quadtrilateral will be impossible if \[\overline{0a}\] is bigger than one half, i.e. if all three points are to the right of the midpoint of the segment. the probability that one is to the right is 1/2 and all three to the right would be \[(\frac{1}{2})^3\]
anonymous
  • anonymous
the same is true for the other three segments, and the probability that each of them is bigger than one half is also 1/8 so the probability of failure is 4 times 1/8 = 1/2 and therefore so is the probability of success.

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