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mathtard
Group Title
Rewrite with rational exponents. Can someone please help me understand and work through this problem?
\[\sqrt[6]{xy^5z}\]
 3 years ago
 3 years ago
mathtard Group Title
Rewrite with rational exponents. Can someone please help me understand and work through this problem? \[\sqrt[6]{xy^5z}\]
 3 years ago
 3 years ago

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polpak Group TitleBest ResponseYou've already chosen the best response.1
Ok well do they want you to rewrite it with fractional exponents? or ?
 3 years ago

mathtard Group TitleBest ResponseYou've already chosen the best response.0
It says rewrite with rational exponents
 3 years ago

simplephysics Group TitleBest ResponseYou've already chosen the best response.0
Okay, well sqrt6 is like a power of 1/6. Let's see if we can apply that..
 3 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.0
\[\sqrt[a]{x}=x^\frac{1}{a}\]
 3 years ago

polpak Group TitleBest ResponseYou've already chosen the best response.1
Ok. So here's basically what you need to know to do all of these problems: \[\huge \sqrt[a]{b^kc^j} = b^{\frac{k}{a}}c^{\frac{j}{a}}\]
 3 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.0
\[\sqrt[a]{b^kc^n}=(b^k c^n)^\frac{1}{a}=b^\frac{k}{a}c^\frac{n}{a}\]
 3 years ago

mathtard Group TitleBest ResponseYou've already chosen the best response.0
so how do I start so I take the b and move it over? make a the denominator and make k and j the numerators?
 3 years ago

polpak Group TitleBest ResponseYou've already chosen the best response.1
The index of your radical what you will divide your powers by.
 3 years ago

polpak Group TitleBest ResponseYou've already chosen the best response.1
There's an 'is' missing from that sentence.
 3 years ago

mathtard Group TitleBest ResponseYou've already chosen the best response.0
I am still confused. I don't know where to begin. I feel like all of these problems are SOOO different
 3 years ago

polpak Group TitleBest ResponseYou've already chosen the best response.1
They are not. Remember the last problem you did? \[\sqrt[4]{(5a)^4} = (5a)^{\frac{4}{4}} = (5a)^1 = 5a\]
 3 years ago

mathtard Group TitleBest ResponseYou've already chosen the best response.0
It is easy to you because you understand I don't. I just don't learn that way. I need to see how it is solved. I have to actually be able to do the problem
 3 years ago

polpak Group TitleBest ResponseYou've already chosen the best response.1
So in this case we have: \[\sqrt[6]{xy^5z}\] We can rewrite it as: \[\large (xy^5z)^{\frac{1}{6}}\]
 3 years ago

polpak Group TitleBest ResponseYou've already chosen the best response.1
And the recall that when you raise a power to a power you multiply the exponents.
 3 years ago

polpak Group TitleBest ResponseYou've already chosen the best response.1
Raise a product to a power that is.
 3 years ago

polpak Group TitleBest ResponseYou've already chosen the best response.1
You just divide each of the exponents by the index of the radical.
 3 years ago

polpak Group TitleBest ResponseYou've already chosen the best response.1
What is the exponent on the x ?
 3 years ago

phi Group TitleBest ResponseYou've already chosen the best response.0
Let's start at the beginning. Do you know how to write \[\sqrt{x}= x^{?}\]
 3 years ago

polpak Group TitleBest ResponseYou've already chosen the best response.1
Correct. So now divide that 1 by 6 and the new exponent on the x will be 1/6
 3 years ago

mathtard Group TitleBest ResponseYou've already chosen the best response.0
thank you.
 3 years ago

polpak Group TitleBest ResponseYou've already chosen the best response.1
Now do the same thing for the y. The exponent on the y is 5, so 5 divided by 6 is 5/6
 3 years ago

polpak Group TitleBest ResponseYou've already chosen the best response.1
Then again for the z and your result is: \[\large x^{\frac{1}{6}}y^{\frac{5}{6}}z^{\frac{1}{6}}\]
 3 years ago

polpak Group TitleBest ResponseYou've already chosen the best response.1
which doesn't seem 'simpler' at all. But that's sometimes how that goes.
 3 years ago

myininaya Group TitleBest ResponseYou've already chosen the best response.0
another general example of applying law of exponent: \[(x^nyz^m)^{r}=(x^ny^1z^m)^r=x^{nr}y^{1r}z^{mr}=x^{nr}y^rz^{mr}\]
 3 years ago
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