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DiogoBest ResponseYou've already chosen the best response.0
arcsec(x) = 1/(sqrt(11/x^2) x^2)
 2 years ago

malevolence19Best ResponseYou've already chosen the best response.1
\[\frac{d}{dx} \sec^{1}(x)=\frac{1}{x\sqrt{x^21}}\] You can drop the 's if x is positive.
 2 years ago

myininayaBest ResponseYou've already chosen the best response.3
let \[y=\sec^{1}(x)\] so \[\sec(y)=x\] therefore \[y'\sec(y)\tan(y)=1\] => \[y'=\frac{1}{\sec(y)\tan(y)}\] but we need this in terms of x sec(y)=x remember! and we can find tan(y) by looking at what sec(y) means sec(y)=hyp/adj=x/1 so the missing side is opposite to y so we can find it by doing sqrt{x^21} so we have \[y'=\frac{1}{x*\frac{\sqrt{x^21}}{1}}=\frac{1}{x \sqrt{x^21}}\]
 2 years ago

myininayaBest ResponseYou've already chosen the best response.3
by the way tan(y) is opposite/adjacent
 2 years ago
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