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101Ryan101
 3 years ago
what's the derivative of cosxsinx
101Ryan101
 3 years ago
what's the derivative of cosxsinx

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satellite73
 3 years ago
Best ResponseYou've already chosen the best response.0product rule \[(fg)'=f'g+g'f\] use \[f(x)=\sin(x), f'(x)=\cos(x), g(x)=\cos(x), g'(x)=\sin(x)\]

lalaly
 3 years ago
Best ResponseYou've already chosen the best response.2f(x)=cos x g(x)=sin x product rule: d/dx ( f(x)g(x) ) = f'(x)g(x) + f(x) g'(x)

101Ryan101
 3 years ago
Best ResponseYou've already chosen the best response.1dy/dx of cosxsinx = (sinx)(sinx) + cosxcosx = cos^2x  sin^2x = ??

lalaly
 3 years ago
Best ResponseYou've already chosen the best response.2yupp thats right....and cos^2xsin^2x = cos(2x)

101Ryan101
 3 years ago
Best ResponseYou've already chosen the best response.1= (1+cos2x)/2  (1cos2x)/2 = 2(cos2x)2 = yeaaaaeee!
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